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Soloha48 [4]
3 years ago
13

An economical substitute for vitreous silica is a high-silica glass made by leaching the B2O3-rich phase from a two-phase borosi

licate glass. (The resulting porous microstructure is densified by heating.) A typical starting composition is 81 wt % SiO2, 4 wt % Na2O, 2 wt % Al2O3, and 13 wt % B2O3. A typical final composition is 96 wt % SiO2, 1 wt % Al2O3, and 3 wt % B2O3. How much product (in kilograms) would be produced from 50 kg of starting material, assuming no SiO2 is lost by leaching
Chemistry
1 answer:
stich3 [128]3 years ago
7 0

Answer:48kg of SiO2, 0.5kg of Al2O3, and 1.5kg of B2O3

Will be the final product

Explanation:

I) 96wt% of SiO2 will amount to 96/100*50 = 0.96*50=48kg of SiO2

ii) 1wt% of Al2O3 will amount to 1/100*50 = 0.01*50=0.5kg of Al2O3

III) 3wt% of B2O3 will amount to 3/100*50 = 0.03*50=1.5kg of B2O3..

The overall product form 48+ 0.5+1.5= 50kg

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Answer:

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Explanation:

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3 years ago
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A sample of an ideal gas at 1.00 atm and a volume of 1.87 L was placed in a weighted balloon and dropped into the ocean. As the
Ludmilka [50]

Answer:

Volume of sample after droping into the ocean=0.0234L

Explanation:

As given in the question that gas is idealso we can use ideal gas equation to solve this;

Assuming that temperature is constant;

Lets P_1 and V_1 are the initial gas parameter before dropping into the ocean

and P_2 and V_2 are the final gas parameter after dropping into the ocean

according to boyle 's law pressure is inversly proportional to the volume at constant temperature.

hence,

P_1V_1=P_2V_2

P1=1 atm

V1=1.87L

P2=80atm

V2=?

After putting all values we get;

V2=0.0234L

Volume of sample after droping into the ocean=0.0234L

7 0
3 years ago
Food in the stomach is broken down by powerful acids and turned into?
zheka24 [161]
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4 0
4 years ago
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What is the vapor pressure of an aqueous solution that has a solute mole fraction of 0.1000? The vapor pressure of water is 25.7
mafiozo [28]

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Use Raoult's Law:

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3 years ago
1. A gas sample at a pressure of 5.00 atm has a volume of 3.00 L. If the gas pressure is changed to 760 mm Hg, what volume will
tatyana61 [14]

Answer:

V₂ =  15.00 atm

Explanation:

Given data:

Initial pressure = 5.00 atm

Initial volume = 3.00 L

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Solution:

P₁V₁ = P₂V₂

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V₂ =  5.00 atm × 3.00 L / 1 atm

V₂ =  15.00 atm

8 0
3 years ago
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