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Nataly_w [17]
3 years ago
15

Dihydrogen sulfide reacts with oxygen gas to form sulfur dioxide and water. How many moles of oxygen gas will react when 0.6469

moles of water are formed?
Chemistry
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer: 0.9704 moles of O_2 will react when 0.6469 moles of water are formed.

Explanation:

The balanced chemical reaction is:

2H_2S+3O_2(g)\rightarrow 2SO_2+2H_2O  

According to stoichiometry :

2 moles of H_2O are formed from = 3 moles of O_2

Thus 0.6469 moles of H_2O are formed from =\frac{3}{2}\times 0.6469=0.9704moles  of O_2

Thus 0.9704 moles of O_2 will react when 0.6469 moles of water are formed.

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Explanation:

<u>Fahrenheit Scale </u>

Fahrenheit temperature scale is the scale which is based on:

(a) For freezing point of the water, 32 °F.

(b) For boiling point of the water, 212 °F.  

With interval between two being divided into equal 180 parts.

<u> Celsius Scale </u>

Celsius temperature scale is the scale which is based on:  

(a) For freezing point of the water, 0 °C

(b) For boiling point of the water, 100 °C.

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<u>Kelvin Scale </u>

It denotes the triple point of water where the solid, liquid, and gas phases exist in equilibrium which is at 273.16 K.

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3 years ago
what is the maximum number of covalent bonds that an oxygen atom with atomic number 8 can make with hydrogen? question 4 options
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Maximum number of covalent bonds that an oxygen atom can make with hydrogen is 2.

  • the ground state electronic configuration of oxygen is 2s² 2p⁴ that means it has 6 electrons in its valence shell and require two electrons are required to complete its octate.
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  • There are no longer any empty orbitals in the octet of oxygen after it is complete. As a result, it is unable to accept more electrons or create more bonds.

Therefore, Oxygen can only generate two bonds because it needs two additional electrons to complete its octet, after which it will run out of empty orbitals in which to receive additional electrons and create additional bonds.

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. Consider the following half-reactions:
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d. Fe(s) and Al(s)

<h3>Further explanation</h3>

In the redox reaction, it is also known  

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

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<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

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So that the metal located on the left can push the metal on the right in the redox reaction  

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Answer:

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Explanation:

Step 1: Write the balanced double displacement reaction

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Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

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Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

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