<u>Answer:</u> The correct answer is Option A.
<u>Explanation:</u>
Iodine is the 53rd element of the periodic table. The number of electrons present in this element are 53.
The electronic configuration of this element = ![[Kr]4d^{10}5s^25p^5](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B10%7D5s%5E25p%5E5)
As, the electrons are filled in the orbitals having n = 5. So, it is present in Period 5.
And, the number of valence electrons of this element is 7. So, it is present in Group 17.
Hence, the correct answer is Option A.