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4 years ago

PLEASE HELP ME!!!! I'm confused....help .....

Mathematics

1 answer:

san4es73 [151]4 years ago

7 0

18
Answer : 7.5 inches

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I need help on the one about slope

pantera1 [17]

I think it is -5
If you divide -1/2 and then 4/1 you will get -5/1 or also known as -5

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2 years ago

I kind of need help. I completely forgot how to do ratios

lana66690 [7]

Answer:

7:5

Step-by-step explanation:

a:b=4:5

a:c=2:7

c:b=7:5

brainliest please!!!<3

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3 years ago

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

6 0

3 years ago

How I do 4 boxes that weighed total of 34 kilograms if each box had the same amount

Blizzard [7]

Each box would have exactly 8.5 kilograms each in them. Hope this helps mate =)

4 0

3 years ago

Read 2 more answers

There are 10 men and 8 women who want to be a part of a commitee of 5 people. If 2 women and 3 men are chosen, how many possible

icang [17]

Their can be 6 arrangements of (2 men to
3 women, and opposite 5 men to 0 women and opposite, 4 men and 1 woman and opposite. so therefore their are 6 arrangements

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3 years ago