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3 years ago

Which is the graph of y = ⌊x⌋ – 2?

Mathematics

1 answer:

Aneli [31]3 years ago

8 0

<h2>Answer:</h2>

The graph is given in the attached image

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N is an integer, write down the values of n such that -15<3n<6

Ira Lisetskai [31]

-15 < 3n < 6

Divide all sides by 3

-5 < n < 2

Now you need all integers between -5 and 2.

-4, -3, -2, -1, 0, 1

3 0

3 years ago

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

3 years ago

B is two-fifth of c

notka56 [123]

Answer:

8a:15b:6c

a:b:c = 8:15:6

7 0

3 years ago

The length of a rectangle is represented by the function L(x) = 5x. The width of that same rectangle is represented by the funct

Mazyrski [523]

Remember that the area of a rectangle is the length of the rectangle multiplied by the width of the rectangle.

In this case, we could say (where $A(x)$ is the area of the rectangle):

$A(x) = L(x) \cdot W(x)$

Substituting the values the problem gave us for $L(x)$ and $W(x)$ , we can find the formula for $A$ in terms of $x$ , which is:

$A(x) = (5x) \cdot (2x^2 - 4x + 13) = (10x^3 - 20x^2 + 65x)$

The formula for the area of the rectangle would be A(x) = 10x³ - 20x² + 65x.

3 0

3 years ago

Read 2 more answers

Please help me with these 6 through 10 :)

drek231 [11]

6.) constant = 75

7.) open sentence = 6 + 22 = 28

8.) equation = 17 + b = 47

9.) solution = when x + 37 = 62, x = 25

3 0

3 years ago