All categories

2 years ago

The area of the rectangle to the right is 68 square feet

Mathematics

1 answer:

den301095 [7]2 years ago

6 0

Step-by-step explanation:

We know that

Area of the rectangle=Length×Breadth

➝(x+4)(x-9)=68

➝x(x-9)+4(x-9)=68

➝x^2-9x+4x+-32=68

➝x^2-5x-32=68

➝x^2-5x=68+32

➝x^2-5x=100

➝x^2-5x-100=0

The equation has no real roots hence this situation can't be possible

You might be interested in

Two questions in picture! Need help!

kkurt [141]

Answer:

1) C) sin(θ) = 119/169

2) D) cos(θ) = 120/169

Step-by-step explanation:

The mnemonic SOH CAH TOA expresses the relationships you need for answering these questions.

Sin(θ) = Opposite/Hypotenuse = 119/169 . . . . . problem 1

Cos(θ) = Adjacent/Hypotenuse = 120/169 . . . . problem 2

5 0

2 years ago

X over 7+4 is greater than or equal to 16

Blizzard [7]

X/11>=16

X>=16x11

X>=176

5 0

3 years ago

Geometry help?<br> 24/10<br> 10/24<br> 24/26<br> 10/26

olasank [31]

24/26 or opposite over adjacent. The answer is C

8 0

3 years ago

What are the solutions of x² + 6x - 16 = 0?

AveGali [126]

Step-by-step explanation:

$x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}}{2\cdot \:1}\\\sqrt{6^2-4\cdot \:1\cdot \left(-16\right)}\\\sqrt{6^2+64}\\\sqrt{36+64}\\\sqrt{100}\\\sqrt{10^2}\\=10\\x_1=\frac{-6+10}{2\cdot \:1},\:x_2=\frac{-6-10}{2\cdot \:1}\\\\\bold{x_1:2}\\\frac{-6+10}{2\cdot \:1}\\\frac{4}{2\cdot \:1}\\\frac{4}{2}\\=2\\\\\bold{x_2:-8}\\\frac{-6-10}{2\cdot \:1}\\\frac{-16}{2\cdot \:1}\\\frac{-16}{2}\\-\frac{16}{2}\\=-8$

Answer:

x₁ = 2

x₂ = -8

6 0

9 months ago

Square MATH has a side length of 7 inches. which three-dimensional object will be formed by continuously rotating square MATH ar

Alla [95]

Answer:

a right cylinder with a radius of 7 inches

4 0

3 years ago