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elena-14-01-66 [18.8K]
3 years ago
11

A triangle has a side length of 3/4 inch and a side length of 3 inches. What could be the length, in inches, of the third side?

Mathematics
1 answer:
Inga [223]3 years ago
6 0
To solve this problem you must apply the proccedure shown below:

 1- If the triangle is a rigth triangle, you must apply the Pythagorean Theorem. Taking the length 3 inches as the hypotenuse, which is the longest side of the triangle, you have:

 a^2=b^2+c^2
 c=√(a^2-b^2)

 b=3/4 inches
 a=3 inches

 2- When you susbtitute the values, you obtain:

 c=√(3 inches)^2-(3/4 inches)^2
 c=2.90 inches

 The answer is: 2.90 inches.
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\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}

2)  Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}.

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1 - Ask: Which two numbers add up to 6 and multiply to -7?

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4) Rewrite the expression with a common denominator.

\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}

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\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}

6) Collect like terms.

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7) Simplify  {y}^{2}+(7y+6y)-6y  to  {y}^{2}+13y-6y

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Step-by-step explanation:

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