Answer:
10 1/2
Step-by-step explanation:
Answer:
Step-by-step explanation:
The string of a kite forms a right angle triangle with the ground. The length of the string represents the hypotenuse of the right angle triangle. The height of the kite represents the opposite side of the right angle triangle.
To determine the height of the kite, we would apply the sine trigonometric ratio which is expressed as
Sin θ = opposite side/hypotenuse.
1) if the kite makes an angle of 25° with the ground, then the height, h would be
Sin 25 = h/50
h = 50Sin25 = 50 × 0.4226
h = 21.1 feet
2) if the kite makes an angle of 45° with the ground, then the height, h would be
Sin 45 = h/50
h = 50Sin45 = 50 × 0.7071
h = 35.4 feet
The approximate difference in the height of the kite is
35.4 - 21.1 = 14.3 feet
The common difference is 12
Further explanation:
It is given that the infinite sequence is an arithmetic sequence
The common difference is the difference between consecutive terms of an arithmetic sequence.
Here,

The common difference is denoted by d.
Here,

The common difference is same for all proceeding terms.
So,
d = 12
Keywords: Infinite arithmetic sequence, Common difference
Learn more about arithmetic sequence at:
#LearnwithBrainly
Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Step-by-step explanation:
I will assume that the exercise says "
times the base and height of Jerry’s rhombus".
The area of a rhombus can be calculated with the following formula:

Where "b" is the length of the base and "a" is the altitude or the height.
Then, you can calculate the area using the formula shown above.
Therefore, you get:
1. Jerry's rhombus:

2. Charlene's rhombus:

Dividing the area calculated, you get:

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.
Answer:
Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq
=√4+9
=√13 <--
or
3.6 units
Given: The two points that are P(5,1) and Q(3,4).
To find: The distance between these two points.
Solution: It is given that there are two points that are P(5,1) and Q(3,4).
The distance between these two points can be found out as using the distance formula that is: 3.6
Thus, the distance between the given two points is 3.6 units.
So you choose 13 or 3.6 Hope this helps :)