3 years ago

Find all roots of the polynomial function F(x)=x^2-2x-24

2 answers:

8 0

$f(x)=x^2-2x-24\\\\
x^2-2x-24=0\\\\
Factorization:\\
x^2+4x-6x-24=0\\\\
x(x-6)+4(x-6)=0\\\\(x+4)(x-6)=0\\\\
x=-4\ \ or \ \ x=6$

liq [111]3 years ago

4 0

$f(x)=x^2-2x-24=x^2+4x-6x-24=x(x+4)-6(x+4)=\\\\=(x+4)(x-6)\\\\f(x)=0\ \ \ \Leftrightarrow\ \ \ (x+4)(x-6)=0\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \Leftrightarrow\ \ \ x+4=0\ \ \ \ \ or\ \ \ \ \ x-6=0\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \Leftrightarrow\ \ \ x=-4\ \ \ \ \ \ \ \ or\ \ \ \ \ x=6$

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ollegr [7]

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2 years ago

Evaluate the following if k=0.5, n=-3, and p=-2: K+n(p^2)

ivann1987 [24]

Answer:

-11.5

Step-by-step explanation:

$K + n( {p}^{2} ) \\ \\ plug \: K = 0.5, \: n = - 3, \: p = - 2 \\ \\ K + n( {p}^{2} ) \\ \\ = 0.5 + ( - 3) \{ {( - 2)}^{2} \} \\ \\ = 0.5 - 3 \{ 4 \} \\ \\ = 0.5 - 12 \\ \\ = - 11.5$