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blondinia [14]
3 years ago
5

Find all roots of the polynomial function F(x)=x^2-2x-24

Mathematics
2 answers:
Paul [167]3 years ago
8 0
f(x)=x^2-2x-24\\\\
x^2-2x-24=0\\\\
Factorization:\\
x^2+4x-6x-24=0\\\\
x(x-6)+4(x-6)=0\\\\(x+4)(x-6)=0\\\\
x=-4\ \ or \ \ x=6
liq [111]3 years ago
4 0
f(x)=x^2-2x-24=x^2+4x-6x-24=x(x+4)-6(x+4)=\\\\=(x+4)(x-6)\\\\f(x)=0\ \ \ \Leftrightarrow\ \ \ (x+4)(x-6)=0\\\\.\ \ \ \ \ \ \ \ \ \ \  \ \ \Leftrightarrow\ \ \ x+4=0\ \ \ \ \ or\ \ \ \ \ x-6=0\\\\.\ \ \ \ \ \ \ \ \ \ \  \ \ \Leftrightarrow\ \ \ x=-4\ \ \ \ \ \ \ \ or\ \ \ \ \ x=6
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The change of base formula is:

log_{b}(y)  =  \frac{ log(y) }{ log(b) }

We apply the change of base formula on the RHS to get:

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Group similar terms:

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From the graph, the logarithmic function approaches negative infinity as x approaches -6.

Therefore the vertical asymptote is x=-6

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