Answer:
At x = 4 ⇒ g(x) = f(2)
Step-by-step explanation:
* In the functions f(x) = 3x - 1 and g(x) = 2x - 3, the domain is
the values of x and the range is the values of y
∵ g(x) = f(2)
* Then you will use the range of f(x) at x = 2 to find the domain of g(x)
∵ The domain of f(x) = 2
∵ f(x) = 3x - 1
∴ f(2) = 3(2) - 1 = 6 - 1 = 5
* The range of f(x) = 5
∵ f(2) = g(x)
∴ 5 = g(x)
∵ g(x) = 2x - 3
∴ 2x - 3 = 5 ⇒ add 3 to both sides
∴ 2x = 8 ⇒ divide both sides by 2
∴ x = 4
* At x = 4 ⇒ g(x) = f(2)
B because it has opposite slopes
Where is it? I can’t help you without it.
Answer:
Given
f(x) = 2x+7
g(x) = x^2-4
h(x) = 5x
a. 4h(x)
= 4 * 5x
= 20x
b. f(x) - g(x)
f(x) - g(x) = 2x + 7 - (x^2 - 4)
= 2x+7-x^2+4
=-x^2+2x+7+4
=-x^2+2x+11
c. f(g(x)) = 2(g(x))+7
=2(x^2-4) +7
=2x^2-8+7
=2x^2-1
d. g(x)h(x) = (x^2-4)(5x)
= 5x^3 - 20x
e. g(x) / f(x) = x2 - 4/ 2x + 7
