Answer:
Ksp = 8.8x10⁻⁵
Explanation:
<em>Full question is:</em>
<em>After mixing an excess PbCl2 with a fixed amount of water, it is found that the equilibrium concentration of Pb2+ is 2.8 × 10–2 M. What is Ksp for PbCl2?</em>
<em />
When an excess of PbCl₂ is added to water, Pb²⁺ and Cl⁻ ions are produced following Ksp equilibrium:
PbCl₂(s) ⇄ Pb²⁺ + 2Cl⁻
Ksp = [Pb²⁺] [Cl⁻]²
If an excess of PbCl₂ was added, an amount of Pb²⁺ is produced (X) and twice Pb²⁺ is produced as Cl⁻ (2X):
Ksp = [X] [2X]²
Ksp = 4X³
As X is the amount of Pb²⁺ = 2.8x10⁻²M:
Ksp = 4(2.8x10⁻²)³
<h3>Ksp = 8.8x10⁻⁵</h3>
Answer:
a) S = 0.0152 mol/L
b) S' = 4.734 g/L
Explanation:
S 2S S...............in the equilibrium
- Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]
a) molar solubility:
⇒ Ksp = ( 2S) ² * S = 1.4 E-5
⇒ 4S² * S = 1.4 E-5
⇒ S = ∛ ( 1.4 E-5 / 4 )
⇒ S = 0.0152 mol/L
b) solubility ( S' ) in grams per liter:
∴ Mw Ag2SO4 = 311.799 g/mol
⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )
⇒ S' = 4.734 g/L
The answer is B I had took that last year
The reactivity of metals increases as you move left in a period and as you move down in a group, so Marie needs to know the period and group of the element inside each box. Boxes that show locations in groups 1 or 2 or in period 8 contain the most reactive elements.
