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Ronch [10]
2 years ago
6

In a mixture of oxygen and nitrogen, 80% of the gas pressure is exerted by the nitrogen. if the total pressure is 2.0 atm, what

pressure does the oxygen exert?
Chemistry
1 answer:
KiRa [710]2 years ago
4 0

0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.

<h3>What is pressure?</h3>

Pressure is defined to be the amount of force exerted per area

80% of pressure is exerted by nitrogen gas.

So, 20% of pressure will be exerted by oxygen gas.

20% of 2.0 atm = 0.4 atm

Hence, 0.4 atm pressure exerted by oxygen if 80% of the gas pressure is exerted by the nitrogen.

Learn more about pressure here:

brainly.com/question/15175692

#SPJ1

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Se sabe que 10 g de calcio reaccionan con 4 g de oxígeno para obtener 14 g de óxido de calcio. Indica la cantidad de óxido de ca
egoroff_w [7]

Answer:

Si se usan 50 gramos de calcio y óxigeno, se obtienen 70 gramos de óxido de calcio.

Explanation:

Hola,

En este caso, la reacción llevada a cabo es:

2Ca+O_2\rightarrow 2CaO

De este modo si asumimos el ejemplo dado, 50 gramos de calcio, cuya masa atómica es 40 g/mol y 50 g de oxígeno, cuya masa atómica como gas diatómico es 32 g/mol, antes de calcular los gramos de óxido de calcio producidos, debemos identificar el reactivo límite. Así, calculamos las moles de calcio disponibles en 50 g:

mol_{Ca}^{disponible}=50gCa*\frac{1molCa}{40gCa} =1.25molCa

Y también las moles de calcio consumidas por los 50 g de oxígeno, utilizando su relación molar 2:1:

mol_{Ca}^{consumidas\ por\ O_2}=50gO_2*\frac{1molO_2}{32gO_2} *\frac{2molCa}{1molO_2} =3.125molCa

Por lo tanto, hay menos calcio disponible que el que consume el oxígeno, por lo que el calcio esel reactivo límite. Ahora, con este, calculamos los gramos de óxido de calcio, cuya masa molar es 56 g/mol, que se producen:

m_{CaO}=1.25molCa*\frac{2molCaO}{2molCa}* \frac{56gCaO}{1molCaO}\\ \\m_{CaO}=70gCaO

Esto quiere decir que de 50 gramos de oxígeno, solo 20 gramos reaccionan para formar 70 gramos de óxido de calcio.

Saludos!

4 0
3 years ago
Read 2 more answers
How many milliliters of water will be created from a combustion reaction with 9.32×10 22nd power of ethanol molecules. Assume de
PolarNik [594]

Answer:

8.38 mL

Explanation:

1- The combustion reaction of ethanol (C2H5OH) in the presence of oxygen (O2) has as reaction products carbon dioxide (CO2) and water (H2O), the equation equaled is:

<em>C2H5OH (l) + 3 O2 (g) CO2 2 CO2 (g) + 3 H2O (l) </em>

2- By establishing the stoichiometric relationship between ethanol and water, you can calculate the number of molecules that will be created from the initial amount of alcohol molecules:

6,022x10 23 molecules of C2H5OH (1 mol) ___ 3 x 6,022x10 23 molecules of H2O (3 moles)

9.32x10 22 C2H5OH molecules _____ X = 2.80x10 23 H2O molecules

<em>Calculation: </em>

9.32x10 22 x (3 x 6.022x10 23) / 6.022x10 23 = 2.80x10 23 H2O molecules

3- Once the number of water molecules formed is obtained, with the molar mass the mass can be determined:

6.022x10 23 H2O molecules _____ 18.02 g

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V = 8.38 g / 1.00 mL = 8.38 mL

The answer is that 8.38 mL of water is formed

5 0
3 years ago
List the 5 chemicals with the highest flash point. (In order, staring with the highest)
Volgvan

Answer:

Flash point of Lube Oil is around the 187°C mark, 

Flash point of Biodiesel of 130°C

Flash point of Diesel Ranging from 52° to 96°

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Answer:

The answer is A

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