Answer:
The enthalpy change during the reaction is -199. kJ/mol.
Explanation:
Mass of solution = m
Volume of solution = 100.0 mL
Density of solution = d = 1.00 g/mL
First we have to calculate the heat gained by the solution in coffee-cup calorimeter.
where,
m = mass of solution = 100 g
q = heat gained = ?
c = specific heat =
= final temperature =
= initial temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the enthalpy change during the reaction.
where,
= enthalpy change = ?
q = heat gained = 2.242 kJ
n = number of moles fructose =
Therefore, the enthalpy change during the reaction is -199. kJ/mol.
Well if you go to bed at 10 well let's hold off on this question so so let's see let's come together so each hour is 60 minutes so let's count if you go to
Answer:
The answer to your question is below
Explanation:
I just write the formulas of the reactants and products and balanced the reactions.
a)
3H₂(g) + N₂(g) ⇒ 2NH₃
b)
2K + 2H₂O ⇒ 2KOH + H₂ (g)
c)
2Al(s) + Fe₂O₃ ⇒ Al₂O₃ + 2Fe
d)
Fe₂O₃ + 2Al ⇒ Al₂O₃ + 2Fe
e)
Ba(OH)₂ + 2HBr ⇒ BaBr₂ + 2H₂O
f)
CaCO₃ + Δ ⇒ CaO + CO₂
Answer:
<h3>Avogadro's hypothesis states that two samples of gas of equal volume, at the same temperature and pressure, contain the same number of molecules. Avogadro's hypothesis allows chemists to predict the behavior of ideal gasses.</h3>
hope it helps
Answer:
The answer to your question is: 62.88 min
Explanation:
Data
Co - 60
half-life = 10.48 min
decay = 1/64 th
Process
1
2 1 half life 1/2 10.48
3 2 half life 1/4 20.96
4 3 half life 1/8 31.44
5 4 half life 1/16 41.92
6 5 half life 1/32 52.4
7 6 half life 1/64 62.88