Part A
<h3>Answer: Yes</h3>
This is the same as saying 2(AB+BC). A more written out version is AB+BC+CD+DA, though it's not needed since the opposite sides are congruent (AB = CD and BC = DA)
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Part B
<h3>Answer: Yes</h3>
The diagonals of any parallelogram bisect each other. They cut each other in half.
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Part C
<h3>Answer: No</h3>
The adjacent sides of a parallelogram aren't always equal in length. It only happens when we have a rhombus.
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Part D
<h3>Answer: Yes</h3>
The angles mentioned are alternate interior angles. They are congruent due to AD and BC being parallel.
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Part E
<h3>Answer: Yes</h3>
We can use the SSS or SAS congruence theorem to prove these triangles are congruent.
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Part F
<h3>Answer: No</h3>
These are adjacent angles that aren't always the same measure. Diagonal AC does not bisect angle DAB. This only happens if we had a rhombus.