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bija089 [108]
3 years ago
7

Whats 2x + y = 10 5x - y = 18 in elimination method

Mathematics
1 answer:
Naya [18.7K]3 years ago
8 0
2x + y = 10
5x - y = 18

7x = 28

x = 4

2(4) + y = 10

8 + y = 10

y = 2

(4,2)
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The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that <em>one</em> side of the equality is equal to the expression of the <em>other</em> side, requiring the use of <em>algebraic</em> and <em>trigonometric</em> properties. Now we proceed to present the corresponding procedure:

\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}

\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }

\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}

\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}

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\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1

\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1

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The <em>trigonometric</em> expression \frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1} is equivalent to the <em>trigonometric</em> expression \sec \alpha \cdot \csc \alpha + 1.

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0
2 years ago
Solve the compound inequality. Then graph the solution set.<br> s-2 &lt;-10 or-3s &lt; 6
xxTIMURxx [149]

Answer:

{s | s < -8 or s >= -2}

Step-by-step explanation:

In order to solve an inequality we simply have to isolate the variable by applying the opposite operations on each side.

s - 2  <  -10   ... add 2 to both sides

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Therefore the final answer would be {s | s < -8 or s >= -2} which is the 3rd graphed multiple choice answer as seen attached to this answer.

4 0
3 years ago
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