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sergij07 [2.7K]
4 years ago
14

Which choice is equivalent to the quotient shown here when x>0

Mathematics
1 answer:
Simora [160]4 years ago
3 0

{\sqrt{\frac{72x^{3}}{50x^{{2}}}} = \frac{\sqrt{72x^{3}}}{\sqrt{50x^{2}}} = \frac {\sqrt{36 * x^{2} * 2 * x}}{\sqrt{25 * x^{2} * 2}} = \frac{\sqrt{36}\sqrt{x^{2}}\sqrt{2}\sqrt{x}}{\sqrt{25}\sqrt{x^{2}}\sqrt{2}} = \frac{6x\sqrt{2x}}{5x\sqrt{2}} = 1\frac{1}{5}\sqrt{x}

The answer is equal to C. \frac{6\sqrt{x}}{5}.

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aleksklad [387]
<span>Hence
2L + C = 1.4
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Add (This will eliminate 'L' )

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