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3 years ago

F(x)=3x^5+7x^3-8x^2-x+23

1 answer:

7 0

Simplifying
f(x) = x2 + 8x + -3

Multiply f * x
fx = x2 + 8x + -3

Reorder the terms:
fx = -3 + 8x + x2

Solving
fx = -3 + 8x + x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -3x-1 + 8 + x

Simplifying
f = -3x-1 + 8 + x

Reorder the terms:
f = 8 + -3x-1 + x

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Substitution:<br><br> y=6x+11<br><br>y-4x=15

german

Answer:

x=2

Step-by-step explanation:

6x+11-4x=15

2x+11=15

2x=4

x=2

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3 years ago

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harina [27]

D,would be the correct answer.

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3 years ago

What is the sum of two numbers a and b decreased by their product?

natka813 [3]

Answer:

(a+b) - (ab)

Step-by-step explanation:

sum of two numbers a and b decreased by their product

(a+b) - (ab)

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3 years ago

Read 2 more answers

What is the scientific notation for a length of 0.0000923 centimeter

nataly862011 [7]

Answer:

9.23*10 to the power 5

Step-by-step explanation:

to move the point 5steps backwards

4 0

3 years ago

Find the equation of an exponential function in the form y = ab^x, given the points (0, 3) and (2, 108/25). Please simplify your

lilavasa [31]

We have the equation:

$y=a\cdot b^x$

We know two points and we will use them to calculate the parameters a and b.

The point (0,3) will let us know a, as b^0=1.

$\begin{gathered} y=a\cdot b^x \\ 3=a\cdot b^0=a \\ a=3 \end{gathered}$

Now, we use the point (2, 108/25) to calcualte b:

$\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}$

Then, we can write the equation as:

$y=3\cdot(\frac{6}{5})^x$

5 0

1 year ago