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3 years ago

What is the value of the unknown number in the verbal description? 5 times the sum of 12 and a number is 80.

Mathematics

2 answers:

S_A_V [24]3 years ago

8 0

Answer: D. 4

Step-by-step explanation:

Let the unknown number be x.

The given verbal description : 5 times the sum of 12 and a number is 80.

i.e. $5(12+x)=80$

To solve the above equation, first divide 5 on both sides of the equation, we get

$12+x=16$

Now, Subtract 12 on the both sides of the equation, we get

$x=16-12=4$

Hence, the unknown number is 4.

mixer [17]3 years ago

4 0

"5 times a sum of 12 and a number is 80" translates to the next equasion:

5 x (12+a) = 80

Now we just have to solve it to find the value of a.
$5 \times (12 + a) = 80 \\ 60 \times 5a = 80 \\ 5a = 80 - 60 \\ 5a = 20 \\ a = 20 \div 5 \\ a = 4$
The unknown number is 4.
D is the right answer.

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3 years ago

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SCORPION-xisa [38]

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2 years ago

Please help! enter a range of values for x:

myrzilka [38]

Answer:

Step-by-step explanation:

using sine formula

let ∠ADB=y

then ∠CDB=180-y

∠DAB =180-(35+y)

$\frac{AB}{sin~y} =\frac{12}{sin ~35}} \\AB=\frac{12 sin y}{sin 35} \\\frac{BC}{sin(180-y)} =\frac{4x-4}{sin 20 } \\\frac{BC}{sin y} =\frac{4x-4}{sin 20} \\BC=\frac{(4x-4)sin y}{sin 20} \\But~AB=BC (given)\\\frac{12 sin y}{sin 35} =\frac{(4x-4)sin y}{sin 20} \\\frac{4x-4}{sin 20} =\frac{12}{sin 35} \\4(x-1)=\frac{12 sin 20}{sin35} \\x-1=\frac{3 sin 20}{sin35} \approx 1.789\\x \approx 2.789$