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3 years ago

What is the value of the unknown number in the verbal description? 5 times the sum of 12 and a number is 80.

Mathematics

2 answers:

S_A_V [24]3 years ago

8 0

Answer: D. 4

Step-by-step explanation:

Let the unknown number be x.

The given verbal description : 5 times the sum of 12 and a number is 80.

i.e. $5(12+x)=80$

To solve the above equation, first divide 5 on both sides of the equation, we get

$12+x=16$

Now, Subtract 12 on the both sides of the equation, we get

$x=16-12=4$

Hence, the unknown number is 4.

mixer [17]3 years ago

4 0

"5 times a sum of 12 and a number is 80" translates to the next equasion:

5 x (12+a) = 80

Now we just have to solve it to find the value of a.
$5 \times (12 + a) = 80 \\ 60 \times 5a = 80 \\ 5a = 80 - 60 \\ 5a = 20 \\ a = 20 \div 5 \\ a = 4$
The unknown number is 4.
D is the right answer.

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(a) The cumulative frequency curve for the data is attached below.

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Step-by-step explanation:

(a)

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The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

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h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

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The formula of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF) $_{p}$ = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

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The value of third quartile is 44.83.

Then the inter-quartile range is:

$IQR = Q_{3}-Q_{1}$

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Thus, the inter-quartile range is 10.08.

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That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

$P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}$

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