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inessss [21]
3 years ago
12

How do you solve this

Mathematics
1 answer:
MissTica3 years ago
5 0

Answer:

The Area is 72.

Step-by-step explanation:

A=1/2d^2

A=1/2(12)^2

A= 1/2(144)

A=72

<em>Hope I helped, Brainliest would be appreciated :) </em>

<em> Have a fantastic day! </em>

<em>                   -Aadi x</em>

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Our pool is twice as long as it is wide and is surrounded by a walkway of uniform width of 1 foot. The
Zigmanuir [339]

Step-by-step explanation:

x=width of pool

2x=length of pool

the dimensions of the rectangle forming the walkway and the pool are x+4 and 2x+4

the area of this rectangle minus the area of the pool is 196 square feet

(2x+4)(x+4)-(x)(2x)=196

2x^2+4x+8x+16-2x^2=196

combine similar terms

12x+16=196

12x=196-16

12x=180

x=180/12

x=15 feet is the width of the pool

check: 34*19-30*15=196

646-450=196

196=196

8 0
3 years ago
Find the values of x and y.<br> X= __<br> Y= __
azamat

Answer:

x = 20

y = 100

Step-by-step explanation:

To figure out x do this.

3x + 2x = 7x - 40 (collect like terms)

5x = 7x -40 (subtract 7x on both sides)

-2x = -40 (divide by -2 on both sides)

x = 20

Plug in to get y

Since 7x - 40 and y are vertical they equal the same amount

7(20) - 40 = y (multiply 7 by 20)

140 - 40 = y (collect like terms)

100 = y

Hope this helps ya! Keep smiling!

6 0
3 years ago
Please help, this is due soon!
Oliga [24]
Before outlier : 7.25
After outlier : 4

7.25 - 4 = 3.25

So the mean decreases by 3.25 when the outlier is removed.
6 0
3 years ago
The radius of a circle is decreasing at a rate of 6.56.56, point, 5 meters per minute. At a certain instant, the radius is 12121
Ilia_Sergeevich [38]

Answer:

The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

Step-by-step explanation:

Given:

\frac{dr}{dt} = -6.5 \ m/min

radius r =12 \ m

We need to find the rate of change of the area of the circle at that instant.

Solution:

Now we know that;

Area of the circle is given by π times square of the radius.

framing in equation form we get;

A= \pi r^2

to find the rate of change of the area of the circle at that instant we need to take the derivative on both side.

\frac{dA}{dt}=\frac{d(\pi r^2)}{dt}\\\\\frac{dA}{dt}= 2\pi r \frac{dr}{dt}

Substituting the given values we get;

\frac{dA}{dt}= 2\times \pi \times 12 \times -6.5\\\\\frac{dA}{dt}\approx -490.09 \ m^2/min

Hence The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

6 0
2 years ago
What is the measure of angle 6?​
Alja [10]

Answer:

smh

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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