I need help with everything

Use Pythagorean theorem to find the missing length. (round to tenth if necessary) IS

sertanlavr [38]

11.7

Formula: a^2 + b^2 = c^2

so substitute the numbers like this:

10^2 + 6^2 = c^2

both 10^2 and 6^2 are perfect squares:

10 × 10= 100 and 6 × 6= 36

100 + 36= c^2

add:

100 + 36 =

136 = c^2

now in order to get rid of the squared, you put it into a radical:

√136 = √c^2

note: whatever you do on one side, you do to the other

it's easier to use the calculator for this so put √136 and you're gonna get 11.66

since it's asking you to round it to the nearest tenth:

11.66 = 11.7

sorry if the explanation is kinda long ✋ i tried explaining it better in the end but i failed

7 0

2 years ago

If a, b, c, d are positive, and if a/b < c/d , then which statement is ALWAYS true?

Dahasolnce [82]

I believe the answer is c

3 0

2 years ago

Read 2 more answers

The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of

Oksanka [162]

Given:

In July:

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

In August:

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

In September:

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

In October:

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

In November:

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

In December:

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

In July,

The difference between the number of days with homework and with no homework = 6-4 = 2

In August,

The difference between the number of days with homework and with no homework = 16-7 = 9

In September,

The difference between the number of days with homework and with no homework = 14-4 = 10

In October,

The difference between the number of days with homework and with no homework = 14-8 = 6

In November,

The difference between the number of days with homework and with no homework = 16-4 = 12

In December,

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

4 0

2 years ago

Substitute to solve Brainliest for correct answer

Ostrovityanka [42]

Answer:

4x-1y=3xy

Step-by-step explanation:

because 3-2=1 and add the y on and the do 4x-1y and that will = 3xy

8 0

2 years ago

Read 2 more answers

Figure ABCD is a parallelogram with point C (−4, 1). Figure ABCD is rotated 90° clockwise to form figure A′B′C′D′. What coordina

Svet_ta [14]

There are certain rules to follow when rotating a point 90 deg clockwise. Since it is given that ABCD is a parallelogram and the coordinates of point C are given, we just have to follow this simple relation:

R(90 deg) : (X,Y) ---> (-Y,X)

Using the given coordinates:
R(90 deg) : (-4,1) ---> (-1,-4)

Therefore, Point C' will be located at (-1,-4)

6 0

2 years ago