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Vsevolod [243]
3 years ago
12

I need help with everything

Mathematics
1 answer:
babymother [125]3 years ago
8 0
Is it a go math book???? if it is say yes

You might be interested in
X = 0<br> Solve.<br> 2.1x - (1 + 2x) = 5.3
HACTEHA [7]

Answer:

<u>-1=5.3</u>

<u />

<em>not sure if this is right; it should be though</em>

<em></em>

Step-by-step explanation:

2.1(0) - (1+2(0))= 5.3

-(1)=5.3

-1=5.3

8 0
3 years ago
The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second.
pickupchik [31]

Answer: first option.

Step-by-step explanation:

The ratio of the area of the triangles can be calculated as following:

ratio_{(area)}=(\frac{l_1}{l_2})^2

Where l_1 is the lenght of the given side of the smaller triangle and l_2 is the lenght of the given side of the larger triangle.

Therefore:

ratio_{(area)}=(\frac{28}{32})^2=\frac{49}{64}

It can be written as following:

ratio_{(area)}=49:64

The ratio of the perimeter is:

ratio_{(perimeter)}=\frac{l_1}{l_2}

Where l_1 is the lenght of the given side of the smaller triangle and l_2 is the lenght of the given side of the larger triangle.

Therefore:

ratio_{(perimeter)}=\frac{28}{32}=\frac{7}{8}

It can be written as following:

ratio_{(perimeter)}=7:8

5 0
3 years ago
The number of girls in the Middle School Cyber Club was 6 more than double the number of boys, and in total there were 48 middle
Wittaler [7]

Answer:

g = number of girls;

b= number of boys

we know that: g= 6+2b

     and that: g+b= 156 kids in total

so we may write  g+b=(6+2b)+b=6+3b

                 but g+b= 156

so 6+3b = 156 => 3b= 156-6=150 =>   b=150/3=50 => b = 50 (number of boys)

g= 6+2b= 6+2 x 50= 106 => g =106 (number of girls)  

Step-by-step explanation:

5 0
3 years ago
Cual es la simplificacion de 72/48​
mina [271]

Answer:

3/2 Alli esta ojala que ayude

3 0
3 years ago
Read 2 more answers
PLEASE I REALLY NEED HELP!
vagabundo [1.1K]

Answer:

\frac{3}{28}

Step-by-step explanation:

Probability (P) is calculated as

P = \frac{requiredoutcome}{count}

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = \frac{3}{8}

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = \frac{2}{7}

P( red and red ) = \frac{3}{8}  × \frac{2}{7} = \frac{6}{56} = \frac{3}{28}

6 0
3 years ago
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