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SCORPION-xisa [38]
3 years ago
8

F(x)=(x+1)^2-8 Give axis of symmetry and vertex

Mathematics
1 answer:
marishachu [46]3 years ago
6 0

\bf ~~~~~~\textit{parabola vertex form}
\\\\
y=a(x- h)^2+ k~\hspace{7em}vertex~~(\stackrel{}{ h},\stackrel{}{ k})
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\stackrel{f(x)}{y}=(x+1)^2-8\implies y=1[x-(\stackrel{h}{-1})]^2+(\stackrel{k}{-8})~\hfill \stackrel{vertex}{(-1,-8)}


the equation is in x-terms, meaning is a vertical parabola, and therefore the axis of symmetry will be the x-coordinate of the vertex, namely x = -1.

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