So if you want to add
we distribute
a(b+c)=ab+ac so
-2(m+n-4)=-2m-2n+8
5(-2m+2n)=-10m+10n
n(m+4n-5)=mn+4n^2-5n
so total we ahve
-2m-2n+8-10m+10n+mn+4n^2-5n
group like terms
4n^2+-2m-10m-2n+10n-5n+mn+8
add like temrs
4n^2-12m+3n+mn+8
Answer:
i don't have a idea
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
First add 1 on both sides, then divide by 4 on both sides
I don’t really know what you talking about but if you mean -2-3 it would be -5