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Serhud [2]
3 years ago
9

Based on Figure 15, determine the solubility of each of the following in grams of solute per 100. g H2O. a. NaNO3 at 10°C b. KNO

3 at 60°C c. NaCl at 50°C
Chemistry
1 answer:
Alina [70]3 years ago
8 0
The solubility of NaNO3 in water at 10 degrees celsius is 80.18 g/100 g water. For KNO3 at 60 degrees celsius, solubility is 108g / 100 g water. Lastly, the solubility of NaCl at a temperature of 50 degrees celsius would be 39 g/ 100 f of water. Hope this helps.
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Classify ethynes as acids
luda_lava [24]
Oxidation of acids giverise acids like oxalic acid and acetic acid
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Addition of halogensAlkynes react with halogens (Cl2<span> or Br</span>2) in the dark, forming dihaloalkenes first and finally tetrahaloalkanes. The reaction gets accelerated in the presence of light or halogen carriers.RCCHRCX=CHXRCX2CX2alkyne dihaloalkene tetrahaloalkaneFor example, ethyne (acetylene) with chlorine gives,ethyne dichloroethene tetrachloroethaneDilute bromine water with ethyne gives dibromo, while liquid bromine gives tetrabromo derivative.tetrabromoethane ethyne 1,2-dibromoethene(acetylene)propyne gives,The order of reactivity is Cl2<span> > Br</span>2<span> > I</span>2.Addition of halogen acidsAlkynes reacts with halogen acids according to the Markownikoff's rule i.e. the carbon atom carrying the least number of hydrogen atoms will have the negative part of the addendum attached to it.For example, ethyne (acetylene) with HBr gives,With diluted HCl at 65°C and in the presence of Hg2+<span> (mercuric ion) ethyne gives vinyl chloride.</span>vinyl chloridePropyne givespropyne 2-bromopropene 2,2-dibromopropaneThe rate of addition of halogen acids follows the order, HI > HBr > HCl
MechanismAddition of hypochlorous acidAlkynes react with hypochlorous acid according to the Markownikoff's rule.For example, ethyne with HOCl gives,dichloroethanalIn the presence of peroxides the addition of HBr takes place according to the anti-MarkowniKoff's rule.Addition of sulphuric acidAlkynes add up two molecules of sulphuric acid. For example, ethyne givesNucleophilic addition reactionsAlkynes also give the following nucleophilic addition reactions.Addition of waterIn the presence of sulphuric acid (42%) and 1 % mercuric sulphate at 60°C, alkynes add on one water molecule to give aldehydes or ketones. For example,alkyne ketoneEthyne gives ethanal and propyne gives acetone.ethyne (acetylene) ethanal (acetaldehyde)
Addition of HCNAlkynes add one molecule of HCN in the presence of Ba(CN)2. For example,Ethyne givesethyne vinyl cyanide
Addition of ozoneOzone adds up across the triple bond to give ozonides. After hydrolysis, ozonides give diketones and carboxylic acids.Ethyne gives glyoxal and formic acid,glyoxal formic acid
Substitution reactionsDue to their acidic nature, alkynes form metallic salts called alkynides e.g., sodium, silver and copper(ous) salts. Examples are,Ethyne (acetylene) has two acidic hydrogen atoms, hence it finally gives dimetal salts.Acidic hydrogen in 1-alkynesHydrogen atoms in ethyne and 1-alkynes, linked to the carbon atom having a triple bond on it, are acidic in nature. For example, ethyne (acetylene) is a weak acid: weaker than water but stronger than ammonia. </span>
4 0
4 years ago
Acids are __________, which means that they “eat away” at other materials. a. basic b. corrosive c. slippery d. litmus
Arte-miy333 [17]

The answer is B. Acids are corrosive.

3 0
3 years ago
Read 2 more answers
Why does ice have a different density than liquid water?
gulaghasi [49]

Answer:

because it has lighter molecules.

4 0
3 years ago
Resources that are not able to be reproduced as quickly as they are used are called _____.
Maurinko [17]

Answer:

C) non renewable resources

Explanation:

These are resources such as oil that are formed over a long period of time but are consumed very quickly.

8 0
3 years ago
Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^---------&gt;Zn E°cell = -0.76 V Cu^2+ + 2 e^-----
Neko [114]

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

5 0
3 years ago
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