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Alex
3 years ago
6

g A student determines the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while th

e crucible is empty, then reweighing the crucible and lid with a sample of the hydrate, heating the crucible and lid with a Bunsen burner and then reweighing the crucible and lid with the sample after cooling to room temperature. Which error will result in too high a value for the amount of water of hydration
Chemistry
1 answer:
katrin2010 [14]3 years ago
3 0

The question is incomplete, the complete question is;

A student determines the number of moles of water in a

hydrated metal oxide by weighing a clean, dry crucible

and lid while the crucible is empty, then reweighing the

crucible and lid with a sample of the hydrate, heating the

crucible and lid with a Bunsen burner and then

reweighing the crucible and lid with the sample after

cooling to room temperature. Which error will result in

too high a value for the amount of water of hydration?

(A) The heating is conducted only once instead of the

three times recommended by the procedure.

(B) The lid is left off the crucible when it is weighed

with the hydrated oxide.

(C) The metal oxide reacts partially with oxygen in the

air, forming a compound in a higher oxidation state.

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Answer:

(D) Some of the heated oxide is spilled from the crucible

before it can be weighed.

Explanation:

It is possible to determine the number of moles of water in a hydrated metal oxide by weighing a clean, dry crucible and lid while the crucible is empty, then reweighing the crucible and lid with a sample of the hydrate. The crucible and lid with the sample are heated, cooled and reweighed.

As this process is going on, suppose some of the heated oxide is spilled from the crucible, then the mass of heated or anhydrous oxide decreases leading to a consequent increase in the number of moles of water in the hydrated metal oxide, hence the answer above.

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