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IgorC [24]
3 years ago
13

Do electrons spin in the same direction within an orbital?​

Chemistry
1 answer:
tester [92]3 years ago
4 0

Answer:

in an atom or molecule, no two electrons can have the same four electronic quantum numbers. As an orbital can contain a maximum of only two electrons, the two electrons must have opposing spins.

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What type of chemical reaction is<br> 10.Pb + FeSO, → PbSO, + far
masha68 [24]

Answer: To balance a chemical equation, enter an equation of a chemical reaction and press the Balance button. The balanced equation will appear above. Use uppercase for the first character in the element and lowercase for the second character.

Explanation:

8 0
4 years ago
The O2 produced from the decomposition of the 1.0 L sample of H2O2 is collected in a previously evacuated 10.0 L flask at 300. K
Sergio [31]

The full question can be seen below:

2H_{2}O_2_{(aq)} --> 2H_{2}O_{(l)}+O_{2}_{g}

The decomposition of H_{2}O_{aq} is represented by the equation above.

A student monitored the decomposition of a 1.0 L sample of H_{2}O_2_(_{aq}_) at a constant temperature of 300K and recorded the concentration of H_{2}O_2 as function of time. The results are given in the table below:

                                    Time (s)      H_{2}O_2

                                    0                 2.7

                                    200            2.1

                                    400            1.7

                                    600            1.4

The O_2_(_{g}_) produced from the decomposition of the 1.0 L sample of H_{2}O_2_(_{aq}_) is collected in a previously evacuated 10.0 L flask at 300 K. What is the approximate pressure in the flask after 400 s?

(For estimation purpose, assume that 1.0 mole of gas in 1.0 L exerts a pressure of 24 atm at 300 K).

Answer:

1.2 atm

Explanation:

Considering all assumptions as stated above;

                       2H_{2}O_2_{(aq)} --> 2H_{2}O_{(l)}+O_{2}_{g}

Initial               2.7 mole               ---             ---

Change          -1.0                        ---             +\frac{1.0}{2}

Equilibrium     1.7 mole                ---             0.5 mole

To determine the concentration of O₂; we need to convert the moles to concentration for O₂ = \frac{0.5}{volume in the flask}

                                  = \frac{0.5 mol}{10.0 L}

                                  = 0.05 \frac{mol}{L}

Thus, based on the assumption that "1.0 mole of gas in 1.0 L exerts a pressure of 24 atm"

∴ 0.05\frac{mol}{L} will give rise to = 0.05 \frac{mol}{L} × 24

                                           = 1.2 atm

7 0
3 years ago
The melting point of copper is 1084°C. How does the energy of the particles in a certain amount of liquid copper compare to the
ipn [44]
The melting point of the solid form of water, which is ice, is 0°C. When we convert both temperatures to kelvin by adding 273 to each we get the melting point of copper as 1357K and that of ice is 273K. Then, dividing the melting point of copper by the melting point of ice, both in absolute temperature scale. The answer would be 4.97. Thus, the energy of molecules of copper is approximately 5 times compared to that of water. 
6 0
4 years ago
(a) How many stereoisomers are possible for 4,4-dimethyl-1,2-cyclopentanediol?
Monica [59]

Answer:

(a) 4 stereoisomers: (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. (b) (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol (c) No, they are optically inactive.

Explanation:

(a) The stereoisomers possible for 4,4-dimethyl-1, 2-cyclopentanediol are (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1S,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2R) 4,4-dimethylcyclopentane1,2-diol. Their structures are shown in the attached file.

(b) The oxidation reaction that occurs between 4,4-dimethylcyclopentene and osmium tetroxide produces (1R,2S) 4,4-dimethylcyclopentane1,2-diol; (1R,2S) 4,4-dimethylcyclopentane1,2-diol. Their structures are also shown in the attached file.

(c) The products of the oxidation reaction in (b) are optically inactive because the compounds contain plane of symmetry that makes them optically inactive compound.

Download docx
5 0
4 years ago
How are tides created on earth?
N76 [4]
The gravitational interaction between the earth and the moon
4 0
3 years ago
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