Answer:
278 cheeseburgers and 350 hamburgers sold on Thursday
Step-by-step explanation:
To confirm that these combined equal 628 we can add them together using the equation 278 + 350. Once confirm that these both equal 628 when combined, we can find the difference between the 350 hamburgers and 278 cheeseburgers by subtracting one from the other using the equation, 350 - 278. When you do that, you will get a difference of 72 which means that there were 72 fewer cheeseburgers sold than hamburgers.
(sorry if this is confusing, I'm not good at explaining things)
Let the number be x.
sqrt(x/4) = 6
x/4 = 6^2 = 36
x = 36 * 4 = 144.
The general formula for an arithmetic sequence is:
a(n) = a + d(n - 1)
a : first term
d : common difference (6)
n : number of the term
In your example, you are told the 6th term is 22.
a(6) = a + 6(6 - 1) = 22
a + 30 = 22
a = 22 - 30
a = -8
So now you have the general formula:
a(n) = -8 + 6(n - 1)
If you like you can simplify it:
a(n) = -8 + 6n - 6
a(n) = 6n - 14
Then you can plug in n = 50:
a(50) = 6(50) - 14
= 300 - 14
= 286
The question asks: "Let
. Find the largest integer n so that <span>f(2) · f(3) · f(4) · ... · f(n-1) · f(n) < 1.98"
The answer is n = 98</span>Explanation:
First thing, consider that the function can be written as:
Now, let's expand the product, substituting the function with its equation for the requested values:
As you can see, the intermediate terms cancel out with each other, leaving us with:
This is a simple inequality that can be easily solved:
200n < 198(n + 1)
200n < 198n + 198
2n < 198
n < 99
Hence, the greatest integer n < 99 (extremity excluded) is
98.
There are no factors, 5 is a prime