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3 years ago

What is the value of x? Enter your answer in the box x=

Mathematics

1 answer:

Vadim26 [7]3 years ago

7 0

Answer: 45°

Step-by-step explanation:

There are 180 degrees in a triangle so

180-80=100-55=45°

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Evaluate the expression. m×n, when m=13 and n=12

Dmitry_Shevchenko [17]

Mxn
13x12
the answer is 156

5 0

3 years ago

Use the whole number product and place value reasoning to place the decimal point in the second product. Explain how you know.

BARSIC [14]

The answer to ypur question is 48.24

5 0

3 years ago

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if Leah makes $9.50 per hour and she works 36 hours this week, how much will her paycheck be before taxes?

Dafna11 [192]

Answer:

Leah makes $342 before tax.

Step-by-step explanation:

9.50 x 36 = 342

Leah makes $342 before tax.

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

3 0

3 years ago

Read 2 more answers

James sold 450 tickets for the community play. Tickets for children cost $2, and tickets for adults cost $5. James sold $1,800 w

nlexa [21]

Answer:

<u>James sold 300 tickets for adults</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of tickets sold by James = 450

Cost of a child ticket = $ 2

Cost of an adult ticket =$ 5

Amount of money collected by James after selling the 450 tickets for the community play = $ 1,800

2. How many tickets for adults did James sell?

x = Number of adult tickets James sold

450 - x = Number of children tickets James sold

For solving for x, we write this equation:

5x + 2 * (450 - x) = 1,800

5x + 900 - 2x = 1,800

3x = 1,800 - 900

3x = 900

x = 900/3 = 300

450 - x = 450 - 300 = 150

<u>James sold 300 tickets for adults and 150 for children</u>

7 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago