Y - y1 = m(x - x1).....this is point slope form
slope(m) = -1
(2,4)...x1 = 2 and y1 = 4
now we sub
y - 4 = -1(x - 2) <===
Answer:
x ≤ 75
Step-by-step explanation:
The computation of the inequality function is as follows:
Let us assume the remaining time left for other drills be x
Given that the team spends 20 minutes for running laps
And minimum of 15 minutes for discussing plays
Also practicing for last one hour and 45 minutes
Now as we know that
1 hour = 60 minutes
So total minutes would be
= 60 + 45
= 105 minutes
Total minutes spend by the team is
= 20 + 15
= 35 minutes
So now the remaining time left is
x ≤ 105 - 35
x ≤ 75
Hi there! So the the new price is $93, and went up from $55. Let's subtract the numbers. 93 - 55 is 38. The change is 38. To find the percent markup, we can write and solve a proportion. Set it up like this:
38/55 = x/100
This is because the amount of change goes above the original (55), and x represents the percent out of 100. We are looking for the markup. Let's cross multiply the values. 100 * 38 is 3,800. 55 * x is 55x. 3,800 = 55x. Now, divide each side by 55 to isolate the x. 55x/55 cancels out. 3,800/55 is 69.0909 or 69 when rounded to the nearest whole number. There. The percent of markup is approx. 69%.
Answer: Fifth grade mean: 4.67
Seventh grade mean: 3.46
Fifth grade median: 5
Seventh grade median: 3.5
Step-by-step explanation: I just did the question
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
