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3 years ago

99 POINTS What is the equation of the line graphed?

Mathematics

2 answers:

Maurinko [17]3 years ago

8 0

Answer:

y = 3x-2

Step-by-step explanation:

We have the y intercept (where it crosses the y axis)

It crosses at y=-2

(0,-2) We need another point to find the slope.

Another point is (1,1)

The formula for slope is

m=(y2-y1)/ (x2-x1)

We have 2 points (0,-2) and (1,1)

= (1--2)/(1-0)

= (1+2)/(1-0)

3/1

m=3

The slope is 3 and the y intercept is -2

We can use the slope intercept form of the equation

y= mx+b where m is the slope and b is the y intercept

y = 3x-2

rjkz [21]3 years ago

3 0

Answer:

y = 3x - 2

Step-by-step explanation:

Two of the coordinates are (2, 4) and (1, 1). The slope of these is 3/1, or 3. Plug this back in to get that the slope-intercept form is y = 3x - 2.

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Which of these is least likely to be the average salary of another of the groups?

Finger [1]

Answer:

$104,000

The probability that the average salary between two groups is the same, is actually low. It could be close, but it's quite difficult to get the same exact amount.

3 0

3 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$