1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Harman [31]
2 years ago
7

5y=2x Can someone explain the steps to solving this

Mathematics
1 answer:
Elena-2011 [213]2 years ago
7 0

Answer:

You can't solve this with only this much info.

Step-by-step explanation:

There are 2 varibles y and x. You have to at least have 2 different equations with only variables y and x or know the value of one. Of course you could guess but then there would be multiple answers. like y=1, x=2.5, etc.

You might be interested in
The time required to drive a fixed distance varies inversely as the speed. It takes 40 hr at a speed of 10 km/h to drive a fixed
patriot [66]

Answer:

50 hours

Step-by-step explanation:

Given data

Time=40hr

Speed=10km/hr

Let us find the fixed distance first

Speed= distance/Time

10= distance/40

distance= 10*40

distance= 400miles

Now our speed= 8km/h

hence the time is

8= 400/time

time= 400/8

time=50 hours

Hence the time is 50 hours

3 0
2 years ago
Is​ f(x) continuous at x equals 4​? Why or why​ not? A. ​No, f(x) is not continuous at x equals 4 because ModifyingBelow lim Wit
soldier1979 [14.2K]

<u>Corrected Question</u>

Is the function given by:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right ​

continuous at x=4​? Why or why​ not? Choose the correct answer below.

Answer:

(D) ​Yes, f(x) is continuous at x = 4 because Lim_{x \to 4}f(x)=f(4)

Step-by-step explanation:

Given the function:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right

A function to be continuous  at some value c in its domain if the following condition holds:

  • f(c) exists and is defined.
  • Lim_{x \to c}$ f(x) exists.
  • f(c)=Lim_{x \to c}$ f(x)

At x=4

  • f(4)=\dfrac{1}{4}*4+1=2
  • Lim_{x \to 4}f(x)=2

Therefore: Lim_{x \to 4}f(x)=f(4)=2

By the above, the function satisfies the condition for continuity.

The correct option is D.

3 0
3 years ago
Is 1.3 million bigger than 65 million
gtnhenbr [62]

Answer:

no

Step-by-step explanation:

because 1.3m is small

and 65M is very big I need 65m

8 0
2 years ago
What is the simplified expression for 3 a squared + 9 a b + 5 minus 4 a squared minus 4 a b + 3? Negative a squared + 5 a b + 8
MArishka [77]

Answer:

The answer is option 1.

Step-by-step explanation:

In order to simplify the expressions, you have to collect like terms :

3a² + 9ab + 5 - 4a² - 4ab + 3

= (3a² - 4a²) + (9ab - 4ab) + (5 + 3)

= -a² + 5ab + 8

7 0
2 years ago
Read 2 more answers
Rectangle EFGH is the image of rectangle ABCD after a sequence of transformations. Which statement describes the transformation
nasty-shy [4]

Answer:

C. Rectangle ABCD was dilated with center (0, 0) and a scale factor of 1/2 followed by a translation right 3.5 units and down 8 units.

Step-by-step explanation:

See figure for intermediate steps.

8 0
3 years ago
Read 2 more answers
Other questions:
  • Add polynomials: (3-4x + 8x^2) + (-6 + 2x - 5x^2)
    9·1 answer
  • What's multipled 3 times equals 91.125
    14·2 answers
  • You buy two T-shirts and I say oh you pay the full price of $12 for the first T-shirt and you get the second T-shirt for have th
    15·1 answer
  • P minute (t) = 5 • (1.03)^t
    9·1 answer
  • 9) y=x+ 11; (4, 13)​
    8·2 answers
  • Find the unknown side length, x. Write your answer in simplest radical form.
    12·1 answer
  • What is the image point of (-1,9) after a translation left 1 unit and<br> down 1 unit?
    12·2 answers
  • 26. Using only digits 0, 1 and 2, this cube has a different
    11·1 answer
  • Maathhhhh tingssssss
    10·2 answers
  • Help please i know its alot but i am in danger of failing for the year if i fail this test :(
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!