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Grace [21]
3 years ago
10

Quick! Need the answer, will give brainiest

Mathematics
2 answers:
Zinaida [17]3 years ago
3 0
Your selection is correct.

A good way to solve these problems is to first figure out the system if the functions were regular equalities. Then, to determine which direction the inequality sign goes, ask whether the graph is shaded above or below y. For above, that means y is greater than... below, less than. A solid line means greater/less than or equal to.
natita [175]3 years ago
3 0
The answer is letter C so you are right
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Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?
pochemuha

Answer:y = negative 3 plus-or-minus StartRoot 5 x + seven-halves EndRoot

Step-by-step explanation: does this help??

5 0
3 years ago
How long does it take a car to travel 200 mi at a constant speed of 25 mi/h?
beks73 [17]
First you have to do 200/25=8.
Since the car is moving at a constant rate, the answer would be 8h.
7 0
3 years ago
Read 2 more answers
What is the perimeter of triangle PQR? Show your work.
xxMikexx [17]

Answer:

The perimeter of triangle PQR is 17 ft

Step-by-step explanation:

Consider the triangles PQR and STU

1. PQ ≅ ST = 4 ft (Given)

2. ∠PQR ≅ ∠STU  (Given)

3. QR ≅ TU = 6 ft (Given)

Therefore, the two triangles are congruent by SAS postulate.

Now, from CPCTE, PR = SU. Therefore,

3y-2=y+4\\3y-y=4+2\\2y=6\\y=\frac{6}{2}=3

Now, side PR is given by plugging in 3 for 'y'.

PR = 3(3) - 2 = 9 - 2 = 7 ft

Now, perimeter of a triangle PQR is the sum of all of its sides.

Therefore, Perimeter = PQ + QR + PR

                                   = (4 + 6 + 7) ft

                                   = 17 ft

Hence, the perimeter of triangle PQR is 17 ft.

7 0
3 years ago
HURRY HURRY HELP MEeeeee
melisa1 [442]

Answer:

dividing by 100

Step-by-step explanation:

6 0
3 years ago
69) Half-way to the center of a planet of uniform density, your weight compared to that at the surface would be :
mel-nik [20]

Answer:

One- half

Step-by-step explanation:

Since the density is uniform  

Mass of the sphere = [(4/3) π r^3] d

where d is the uniform density.

Mass of the sphere = [(4/3) π d] r^3 = k r^3

where k = [(4/3) π d] is a constant  

Weight = mg = G m M / r^2 = G m [k r^3] /r^2 = G m k r

Using Gauss’ law for gravitation,

Half way to the center of a planet the weight is only due to the inner sphere and the outer sphere does not contribute to his weight,  

Inside his weight is mg’ = (G m k  r) /2   = mg/2  

Answer is one-half.

7 0
3 years ago
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