Mrs William's has 42 apples and d
1 answer:
You might be interested in
<h3>Answer: (2, 2)</h3>
==============================================
Explanation:
The phrasing "translated along <4,6>" is another way of saying "shift 4 to the right, shift 6 up"
In general, "translated along <m,n>" is the same as writing . If m is positive, then we shift m units to the right. If m is negative, then we shift to the left. The same story happens with the n, but we focus on the y coordinate.
-------------
With all that in mind, starting at F(-5,-9) and translating along <4,6> has us arrive at (-1, -3). Add 4 to the x coordinate and add 6 to the y coordinate.
We can say
Showing that (-5,-9) moves to (-1,-3)
This is after the first translation, but there's a second translation.
We'll apply the same idea, but different numbers this time
So (-1,-3) moves to (2,2)
Overall we have
- (-5,-9) move to (-1,-3) after the first translation
- (-1,-3) move to (2,2) after the second translation
Therefore, the original point ends up at (2,2) which is the final answer
--------------
Extra info:
A nice shortcut is that the vectors <4,6> and <3,5> can be added to get <4+3,6+5> = <7,11>. So overall, we're shifting 7 units to the right and 11 units up when we combine the two translation vectors.
Finding the upper and lower bounds for a definite integral without an equation is pretty hard because how can we find the upper and lower bounds of definite integral if there is no equation given. But I will teach you how to find the lower and upper bounds of a definite integral, when the equation is like this
So, i integrate this,
I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4
So, i integrate this,
I know I have a minimum at x=3 because;
f(t )= t^2 − 6t + 11
f′(t) = 2
t−6 = 0
2(t−3) = 0
t = 3
f(5) = 4
f(1) = −4