a counterclockwise rotation about the origin of 90°
The coordinates of P(3, 3), Q(5, 3), R(5, 7)
The coordinates of P'(- 3, 3 ), Q'(- 3, 5), R'(- 7, 5)
Note that the y-coordinate of the image is the negative of the original, while the x-coordinate of the original becomes the y-coordinate of the image
The rotation which does this is a counterclockwise rotation about the origin of 90°
a point (x, y ) → (- y, x )
A = 21/2 i will write something too just to fill up the space
If triangles PQR and STU are similar then PQ corresponds to ST and PR corresponds to SU. Therefore, PQ/ST=PR/SU
Considering that, PQ= 7-x, ST= 13-x, PR= x²+5 and SU= x² +20
therefore, (7-x)/(13-x)= (x²+5)/(x²+20)
cross multiplying,
7x² +140-x³+20x =13x²+65-x³-5x
combining the like terms,
6x² +15x -75=0
solving for x,
x = 5/2 or -5
Answer:
11
Step-by-step explanation:
2 times 6 is 12 minus 1 is 11
Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
