Answer is: number is 0.14303691.
Carbon-13 (¹³C) is a stable isotope of carbon with mass number 13, it has six protons and seven neutrons.
Isotopes are chemical elements with same atomic number, but different mass number (different number of neutrons).
ω(¹³C) = 1.10% ÷ 100%.
ω(¹³C) = 0.0110; abundance of carbon-13 in nature.
m(¹³C) = 13.003355; the atomic mass of carbon-13.
ω(¹³C) · m(¹³C) = 0.0110 · 13.003355.
ω(¹³C) · m(¹³C) = 0.14303691.
Answer:
P = 27.07 atm
Explanation:
Given that,
The number of moles, n = 22.5 mol
Volume, V = 30.5 L
Temperature, T = 447 K
We need to find the pressure of the gas. The ideal gas law is as follows :

R = 0.0821 L-atm/mol-K
Put all the values,

So, the pressure of the gas is 27.07 atm.
Answer:
contain hereditary information
break down food into energy
Explanation:
Hereditary information is contained in genes and genes are found inside the cell. This implies that the cell contains hereditary information of organisms. This hereditary information is passed on during cell division from parent to daughter cells.
Metabolism occurs in the cells. The cells use oxygen to break down food materials to produce energy.
<u>Answer:</u> The
for HCN (g) in the reaction is 135.1 kJ/mol.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:
For the given chemical reaction:

The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20H_f_%7B%28HCN%29%7D%29%2B%286%5Ctimes%20%5CDelta%20H_f_%7B%28H_2O%29%7D%29%5D-%5B%282%5Ctimes%20%5CDelta%20H_f_%7B%28NH_3%29%7D%29%2B%283%5Ctimes%20%5CDelta%20H_f_%7B%28O_2%29%7D%29%2B%282%5Ctimes%20%5CDelta%20H_f_%7B%28CH_4%29%7D%29%5D)
We are given:

Putting values in above equation, we get:
![-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ](https://tex.z-dn.net/?f=-870.8%3D%5B%282%5Ctimes%20%5CDelta%20H_f_%7B%28HCN%29%7D%29%2B%286%5Ctimes%20%28-241.8%29%29%5D-%5B%282%5Ctimes%20%28-80.3%29%29%2B%283%5Ctimes%20%280%29%29%2B%282%5Ctimes%20%28-74.6%29%29%5D%5C%5C%5C%5C%5CDelta%20H_f_%7B%28HCN%29%7D%3D135.1kJ)
Hence, the
for HCN (g) in the reaction is 135.1 kJ/mol.