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My name is Ann [436]
3 years ago
5

Metallic behavior is generally associated with elements with partially filled p orbitals. elements with unpaired electrons. elem

ents with small atomic radii. elements with very negative electron affinities. elements with low ionization energies.
Chemistry
1 answer:
Mila [183]3 years ago
4 0

Answer:

Elements with low ionization energies.

Explanation:

The ionization energy of an atom reffers to the amount of energy that is required to remove an electron from the gaseous form of that atom or ion.

The greater the ionization energy, the more difficult it is to remove an electron. The ionization energybis one of the indicator that shows the reactivity of an element. Elements with a low ionization energy such as metals are usually reffered to as a reducing agents and form cations, this give metals the tendency to

give away their valence electrons when bonding, whereas non-metals tend to take electrons.

Metallic elements have different properties such as shiny, heat and electricity conductivity . They are malleable and ductile Some metals, such as sodium, are soft and can be cut with a knife. while some are very hard such as iron.

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The atomic mass of 13C is 13.003355. Multiply the atomic mass of 13C by its abundance. Report the number to 8 significant digits
arsen [322]

Answer is: number is 0.14303691.

Carbon-13 (¹³C) is a stable isotope of carbon with mass number 13, it has six protons and seven neutrons.

Isotopes are chemical elements with same atomic number, but different mass number (different number of neutrons).

ω(¹³C) = 1.10% ÷ 100%.

ω(¹³C) = 0.0110; abundance of carbon-13 in nature.

m(¹³C) = 13.003355; the atomic mass of carbon-13.

ω(¹³C) · m(¹³C) = 0.0110 · 13.003355.

ω(¹³C) · m(¹³C) = 0.14303691.

4 0
3 years ago
Calculate the pressure using the formula P=1.03+ mass on syringe/area of top of syringe
vazorg [7]
Mass divided by volume
6 0
4 years ago
If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?
Fantom [35]

Answer:

P = 27.07 atm

Explanation:

Given that,

The number of moles, n = 22.5 mol

Volume, V = 30.5 L

Temperature, T = 447 K

We need to find the pressure of the gas. The ideal gas law is as follows :

PV=nRT\\\\P=\dfrac{nRT}{V}

R = 0.0821 L-atm/mol-K

Put all the values,

P=\dfrac{22.5\times 0.0821\times 447}{30.5}\\\\P=27.07\ L

So, the pressure of the gas is 27.07 atm.

8 0
3 years ago
Choose all the answers that apply. What do all cells do? reproduce contain hereditary information have a nucleus break down food
Travka [436]

Answer:

contain hereditary information

break down food into energy

Explanation:

Hereditary information is contained in genes and genes are found inside the cell. This implies that the cell contains hereditary information of organisms. This hereditary information is passed on during cell division from parent to daughter cells.

Metabolism occurs in the cells. The cells use oxygen to break down food materials to produce energy.

5 0
3 years ago
Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---> 2HCN (g) + 6H2O (g) delta
AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

8 0
3 years ago
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