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Luden [163]
3 years ago
12

When 2.50g of hydrochloric acid reacts with 1.50g of potassium hydroxide to yiel

Chemistry
1 answer:
zaharov [31]3 years ago
5 0

1.50  grams of potassium chloride are produced

<u>Potassium hydroxide</u> is the limiting reactant

Explanation:

HCl + KOH→KCl + H₂O

HCl and KOH react on a 1 : 1 mole ratio. They also produce products on a 1 : 1 ratio.

The limiting reagent, in this case, is KOH because it will be fully exhausted in the reaction while the excess HCl will be left remaining.

The remaining HCL will be 2.50 g – 1.50 g

= 1g

Remember because both reactants react at a 1: 1 ratio

In addition, 1.50 g on KCl will be formed in the products

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3 years ago
Read 2 more answers
Why does the pink color, which forms at the point where NaOH comes into contact with the solution (HCl) in the flask, disappear
Novay_Z [31]
Answer is: because pH value of solution is changing.
Balanced chemical reaction: NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l).
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3 years ago
A certain ore is 24.3% nickel by mass. how many kilograms of this ore would you need to dig up to have 55.0 g of nickel?
zysi [14]
Let x be the mass of the ore in grams such that the equation that would allow us to answer this item would be,

                     55 = (x)(0.243)

The value of x is calculated as,

                 x = 55/0.243
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4 0
3 years ago
write a balanced chemical reaction when heated aluminium metal react with solid copper oxide produce copper metal and aluminium
prohojiy [21]

Answer:

<h2>2Al + 3CuO ==> 3Cu + Al2O3</h2>

Explanation:

So let's break this chemical equation down into 2 parts - Reactants and Products

Reactants = Al + CuO

Products = Cu + Al2O3

So the Chemical Reaction will be

Al + CuO ==> Cu + Al2O3

So the balanced equation will be,

2Al + 3CuO ==> 3Cu + Al2O3

PLS mark as brainliest

3 0
3 years ago
A certain liquid X has a normal boiling point of 111.20 celsius and a boiling point elevation constant Kb=0.95. calculate the bo
Goshia [24]

Answer: the boiling point is = 137.325°C

Explanation:

From the formula: ∆Tb= Kb*m

From the question, Kb= 0.95, m= 27.5, T1= 111.2°C

Substitute into ∆Tb= Kb*m

∆Tb= 0.95*27.5= 26.125

∆Tb= T2-T1

Hence

T2- 111.2=26.125

T2= 26.125+ 111.2= 137.325°C

8 0
3 years ago
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