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3 years ago

When 2.50g of hydrochloric acid reacts with 1.50g of potassium hydroxide to yiel

Chemistry

1 answer:

zaharov [31]3 years ago

5 0

1.50 grams of potassium chloride are produced

<u>Potassium hydroxide</u> is the limiting reactant

Explanation:

HCl + KOH→KCl + H₂O

HCl and KOH react on a 1 : 1 mole ratio. They also produce products on a 1 : 1 ratio.

The limiting reagent, in this case, is KOH because it will be fully exhausted in the reaction while the excess HCl will be left remaining.

The remaining HCL will be 2.50 g – 1.50 g

= 1g

Remember because both reactants react at a 1: 1 ratio

In addition, 1.50 g on KCl will be formed in the products

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Answer:

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Explanation:

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Unknown:

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3 years ago

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Answer:

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3 years ago

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Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe

jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

$n=\frac{m}{M_m}$

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

$n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol$

Now we can find the pressure of the gas by using the ideal gas law:

$pV=nRT$

where

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3 years ago

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nexus9112 [7]

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