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Luden [163]
3 years ago
12

When 2.50g of hydrochloric acid reacts with 1.50g of potassium hydroxide to yiel

Chemistry
1 answer:
zaharov [31]3 years ago
5 0

1.50  grams of potassium chloride are produced

<u>Potassium hydroxide</u> is the limiting reactant

Explanation:

HCl + KOH→KCl + H₂O

HCl and KOH react on a 1 : 1 mole ratio. They also produce products on a 1 : 1 ratio.

The limiting reagent, in this case, is KOH because it will be fully exhausted in the reaction while the excess HCl will be left remaining.

The remaining HCL will be 2.50 g – 1.50 g

= 1g

Remember because both reactants react at a 1: 1 ratio

In addition, 1.50 g on KCl will be formed in the products

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1s to the second power, 2s to the second power, 2p to the 6th power, 3s to the second power and 3p to the third power.
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A flask with a volume of 250.0 mL contains air with a density of 1.164 g/L. What is the mass of the air contained in the flask?
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1 year ago
Chlorine has an atomic number of 17.
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Read 2 more answers
What is the new concentration of 25.0mL added to 125.0mL of 0.150M
____ [38]

Answer:

The new concentration is 0.125 M.

Explanation:

Given data:

Initial volume V₁ = 125.0 mL

Initial molarity M₁ = 0.150 M

New volume V₂ = 25 mL +125 mL = 150 mL

New concentration M₂ = ?

Solution:

M₁V₁    =    M₂V₂

0.150 M × 125 mL = M₂ × 150 mL

M₂ = 0.150 M × 125 mL / 150mL

M₂ = 18.75 M.mL/150 mL

M₂ = 0.125 M

The new concentration is 0.125 M.

8 0
3 years ago
A gas occupies a volume of 31.0 ml at 19.0°C. If the gas temperature rises to 38.0°C at constant pressure. Calculate the new vol
Alik [6]

Answer:

The correct answer is 0.0033 L (33.0 mL)

Explanation:

We uses the Charles's law which describes the changes in the volume (V) of a gas and its temperature in Kelvin (T) at constant pressure. The mathematical expression is the following:

V₁/T₁ = V₂/T₂

We have the following data:

V₁= 31.0 mL = 0.0031 L

T₁= 19.0°C = 292 K

T₂= 38.0°C = 311 K

V₂= ?

We calculate V₂ from the mathematical expression, as follows:

V₂= V₁/T₁ x T₂ = 0.0031 L/(292 K) x 311 K = 0.0033 L

5 0
2 years ago
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