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Genrish500 [490]
3 years ago
10

Problem 11. A, B, C, D, E, F,

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

Your answer will be D.

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I need help with this question ):
steposvetlana [31]

Answer:

b

Step-by-step explanation:

its b since you have -1 -2 so its x+1 and x+2

will you try to help me on my question i posted to day

5 0
3 years ago
What is 0.6 x 2.2 = ?
Mariulka [41]
Your answer is 1.32                  
4 0
3 years ago
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Explain in sentences how you can add or subtract two fractions with common denominators?
Lemur [1.5K]
If two fractions have the same denominators, then just simply add up the numerators together and keep the denominator.

Examples:

\frac{4}{10} +  \frac{5}{10} =  \frac{9}{10}

\frac{10}{12} - \frac{2}{12} = \frac{8}{12}
8 0
3 years ago
A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced.
zzz [600]

Answer:

CI=(66.54,78.46)                                  

Step-by-step explanation:

Given : A new catalyst is being investigated for use in the production of a plastic chemical. Ten batches of the chemical are produced. The mean yield of the 10 batches is 72.5% and the standard deviation is 5.8%. Assume the yields are independent and approximately normally distributed.

To find : A 99% confidence interval for the mean yield when the new catalyst is used ?

Solution :

Let X be the yield of the batches.

We have given, n=10 , \bar{X}=72.5\% , s=5.8%

Since the size of the sample is small.

We will use the student's t statistic to construct a 995 confidence interval.

\bar X\pm t_{n-1,\frac{\alpha}{2}}\frac{s}{\sqrt n}

From the t-table with 9 degree of freedom for \frac{\alpha}{2}=0.005

t_{n-1,\frac{\alpha}{2}}=t_{9,0.005}

t_{n-1,\frac{\alpha}{2}}=3.250

The 99% confidence interval is given by,

CI=72.5 \pm 3.25\frac{5.8}{\sqrt{10}}

CI=72.5 \pm 5.96

CI=(72.5+5.96),(72.5-5.96)

CI=(66.54,78.46)

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3 years ago
Q.18 - Please help! I will give Brainliest!!!
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ANSWER:  x will equal  3 I hope this helps
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3 years ago
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