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Papessa [141]
2 years ago
15

If the units for x are years, and x = 5 represents the year 2015, what is the y-value for 2010?

Mathematics
1 answer:
Darya [45]2 years ago
5 0

<u>Given</u>:

The given graph passes through the points (-3,4) and (3,2)

The x - axis represents the years. The value x = 5, year 2015.

We need to determine the y - value for 2010.

<u>Slope</u>:

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (-3,2) and (3,2), we get;

m=\frac{2-4}{3+3}

m=\frac{-1}{3}

Thus, the slope of the line is m=\frac{-1}{3}

<u>y - intercept:</u>

The y - intercept in the graph is the point in the line that crosses the y - axis.

Thus, from the graph, it is obvious that the y - intercept is b = 3.

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y=mx+b

Substituting the values, we have;

y=-\frac{1}{3}x+3

Thus, the equation of the line is y=-\frac{1}{3}x+3

<u>The y - value for 2010:</u>

Since, it is given that x = 5 represents 2015 and 2010 is 5 years before 2010.

Hence, the value of x for 2010 is given by

x=5-5=0

Thus, x = 0 represents the year 2010.

To determine the y - value, let us substitute x = 0 in the equation y=-\frac{1}{3}x+3, we have;

y=-\frac{1}{3}(0)+3

y=3

Thus, for 2010 the value of y is 3.

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Answer:

The student's overall grade is 85.79%

Step-by-step explanation:

Given in the question that:

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A particular student scored the following;

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Calculating the percentages the student had for each;

Exam total = 50*0.879 = 43.95% earned

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Total earned = 43.95+ 23.34 + 13.5+ 5 = 85.79%

3 0
3 years ago
On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/
den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

Speed=\dfrac{Distance}{Time}

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

2.5=\dfrac{d}{t}

2.5t=d      ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

4=\dfrac{d}{t-15}

4(t-15)=d      ...(2)

From (1) and (2), we get

4(t-15)=2.5t

4t-60-2.5t=0

1.5t=60

t=40

Put t=40 in (1).

d=2.5(40)=100

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}

\text{Average speed}=\dfrac{200}{65}

\text{Average speed}\approx 3.08

Therefore, the average speed is 3.08 km/h.

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3 years ago
In 1990, 1000 adults were randomly selected and each was asked if they smoked, 300
Oduvanchick [21]

Answer:

 The proportion of smokers was higher in 1990 than in 2000

Step-by-step explanation:

Solution

Recall that,

The total number of sample 1 (n1) = 1000

Total  sample 2 number  (n2) = 2000

The number of favourable events (X1) = 300

The number of favourable events (X2) = 500

so,

p₁ = X₁/n₁ = 300/1000 = 0.3

p₂ = X₂/n₂ =500/2000 =0.25

α = 0.05

We are interested in testing the hypothesis.

The  hypothesis (Null) ....>  H₀ : p₁ = p₂

Alternate hypothesis------ > H₁ : p₁ > p₂

Thus,

P = X₁ + X₂/ n₁ + n₂

P =300 + 500/1000 +2000

P =800/3000

=0.2667

Now,

Z₀ = P₁ - P₂/√ P (1 -P) (1/n₁ + 1/n₂)

Z₀ =  0.3 - 0.25/√0.2667  (1 - 0.2667) (1/1000 + 1/2000)

Z₀ = 0.4999999999999999/√ 0.2667 (0.7333000000000001) (0.001 +0.0005)

Then,

Z₀ = 0.4999999999999999/√0.00029335666500000004

Z₀ = 2.9193

so,

zα/2 = z0.05/2 =z0.025

zα/2 = 1.6448536269514722

Now, we apply the decision rule:

Decision Rule: Reject the null hypothesis if the statistic value test is higher than the critical value 1.6448536269514722

The statistic value, 2.9193 is greater than the critical value 1.6448536269514722,  then we will reject the null hypothesis.

Therefore, the proportion of smokers was higher in 1990 than in 2000

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