<u>Given</u>:
The given graph passes through the points (-3,4) and (3,2)
The x - axis represents the years. The value x = 5, year 2015.
We need to determine the y - value for 2010.
<u>Slope</u>:
The slope of the line can be determined using the formula,
![m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Substituting the points (-3,2) and (3,2), we get;
![m=\frac{2-4}{3+3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B2-4%7D%7B3%2B3%7D)
![m=\frac{-1}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-1%7D%7B3%7D)
Thus, the slope of the line is ![m=\frac{-1}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B-1%7D%7B3%7D)
<u>y - intercept:</u>
The y - intercept in the graph is the point in the line that crosses the y - axis.
Thus, from the graph, it is obvious that the y - intercept is b = 3.
<u>Equation of the line:</u>
The equation of the line can be determined using the formula,
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
Substituting the values, we have;
![y=-\frac{1}{3}x+3](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B3%7Dx%2B3)
Thus, the equation of the line is ![y=-\frac{1}{3}x+3](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B3%7Dx%2B3)
<u>The y - value for 2010:</u>
Since, it is given that x = 5 represents 2015 and 2010 is 5 years before 2010.
Hence, the value of x for 2010 is given by
![x=5-5=0](https://tex.z-dn.net/?f=x%3D5-5%3D0)
Thus, x = 0 represents the year 2010.
To determine the y - value, let us substitute x = 0 in the equation
, we have;
![y=-\frac{1}{3}(0)+3](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B3%7D%280%29%2B3)
![y=3](https://tex.z-dn.net/?f=y%3D3)
Thus, for 2010 the value of y is 3.