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2 years ago

Find the distance from point a (7/8, -1/8) to point b (-1/8, 7/8)

Mathematics

1 answer:

VashaNatasha [74]2 years ago

3 0

Answer:

sqrt(2) ≈1.414213562

Step-by-step explanation:

Distance is found by the formula

d =sqrt ( (x2-x1)^2 + (y2-y1)^2)

= sqrt( (-1/8 - 7/8)^2 + (7/8 --1/8)^2)

sqrt( (-8/8)^2 + (7/8 +1/8)^2)

sqrt( (-1)^2 + (1)^2)

sqrt ( 1 +1)

sqrt(2)

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Answer:

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Step-by-step explanation:

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2 years ago

The population, p, of a town after t years is represented using the equation p=10000(1.04)^-t Which of the following is an equiv

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Answer:

p=10000(26/25)t

Step-by-step explanation:

Considering that the population, p, of a town after t years is represented using the equation p=10000(1.04)^-t

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2 years ago

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13x=-21-6y and -8x=36+6y

IgorLugansk [536]

Answer:

$x=3\\y=-10$

Step-by-step explanation:

$13x=-21-6y\\-8x=36+6y$

Let's take one of the equations and solve for x. I'll take the first one.

$13x=-21-6y$

Divide by 13.

$x=\frac{-21-6y}{13}$

Now replace x in the second equation.

$-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y$

Distribute -8

$\frac{168+48y}{13}=36+6y$

Break down the fraction.

$\frac{168}{13}+\frac{48}{13}y=36+6y$

Subtract $\frac{168}{13}$

$\frac{48}{13}y=36+6y-\frac{168}{13}$

Subtract 6y

$\frac{48}{13}y-6y=36-\frac{168}{13}$

Combine like terms;

$\frac{48-13*6}{13}y=\frac{36*13-168}{13}$

Solve;

$\frac{48-78}{13}y=\frac{468-168}{13}$

Keep solving;

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Multiply by the negative reciprocal of the fraction next to y.

$(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )$

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

$y=-10$

After having found y, replace it in any of the equations to find x.

$13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3$

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