Question is not well presented
Consider the binomial distribution with n trials and P(S) = p.
Show that
p(y) /p(y − 1) = (n − y + 1)p /yq > 1 if y < (n + 1)p.
This establishes that p(y) > p(y − 1) if y is small (y < (n + 1)p) and p(y) < p(y − 1) if y is large (y > (n + 1) p). Thus, successive binomial probabilities increase for a while and decrease from then on.
Answer:
See Explanation Below
Step-by-step explanation:
Given that
p(y) /p(y − 1) = (n − y + 1)p /yq > 1 if y < (n + 1)p.
First, we make the following assumption
p(y) /p(y − 1) = (n − y + 1)p /yq = 1;
So, we have
(n − y + 1)p /yq = 1
(n − y + 1)p = yq
Note that p + q = 1;.
So, q = 1 - p
Substitute 1-p for q in the above expression
(n − y + 1)p = y(1-p)
np - py + p = y - py
Solve for y
..... Collect like terms
np + p = y - py + py
np + p = y;
So, y = np + p
y = (n + 1)p
From the above,
We know that
p(y) /p(y − 1) = 1
if y = (n + 1)p.
Similarly, we've also obtain that
p(y) /p(y − 1) > 1 if y < (n + 1)p.
Round 1,627,187 to the nearest ten = 1,627,190
3x-6 this is the answer because it rose 3 and the Y intercept is -6
Quotient means that division was used so you do the opposite of division which is multiplication... so you do 12×2 and get 24 ...so 24 fast songs were played
Answer:
AC = BC = 5
AB = 5√2
∠A = ∠B = 45
∠A = 90
Step-by-step explanation:
AC = 5 ( Reason : 5 squares are present in between A and C )
Similarly,
BC = 5
<u>By Pythagoras theorem</u>,
(AB)² = (AC)² + (BC)²
= 5² + 5²
= 2 * 5²
(AB)² = 2 * 5²
AB = 5√2
Since, sides AC and BC are equal,
∠A = ∠B = 45
Since, AC is perpendicular to BC,
∠A = 90
