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3 years ago

Please help: Solve the equation

Mathematics

1 answer:

natka813 [3]3 years ago

3 0

Answer:

x < -32

Step-by-step explanation:

What Value would be needed to fulfill this?

Let's first move the eight to the other side.

$x-\frac{3}{4}x$

$\frac{1}{4}x$

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ASAP HELPP PLEASE ?

Kipish [7]

1. h = -16t² + vt + c
⇒ vt = 16t² + h - c
⇒ v = 16t + (h-c)/t

2. c = 5 ft
t = 3s
h = 131 ft

v = 16*3 + (131-5)/3 = 48 + 42 = 90 ft/s

when t=0, velocity is not defined. That means at t=0, there is no velocity of the t-shirt or it is 0.

5 0

3 years ago

Read 2 more answers

What is the value of x?

frez [133]

$\left\{\begin{array}{ccc}x+2y=4&\text{multiply both sides by 5}\\4x-5y=42&\text{multiply both sides by 2}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}5x+10y=20\\8x-10y=84\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad13x=104\qquad\text{divide both sides by 13}\\\\\boxed{x=8}\\\\Answer:\ \boxed{\boxed{x=8}}$

5 0

3 years ago

Fran works due north of home. Her husband Juan works due east. By the time Fran is 5 miles from home the distance between them i

lana66690 [7]

If I understood the question correctly, let's set the coordinates (5,5) from the origin (the home). To find the longer side of the triangle, (the distance between the husband and wife), we use A squared * B squared= C squared. 25*25=625, the square root of 625 is 25. So the distance between the husband and wife would be 25 miles. Therefore, one mile less than their distance would be 24 miles. To answer your question, Juan is 24 miles from home.

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3 years ago

Kyndal wants to buy a lamp that

fenix001 [56]

Answer:

$39.36

Step-by-step explanation:

Since its 20% off that means we still have a remaining 80% so first multiply 0.8 to the 82

82x0.8= 65.6

Since there is a additional 40% off multiply by 0.4 to get the discount amount

65.6x0.4= 26.24

Subtract the discount from the price

65.6-26.24= 39.36

5 0

3 years ago

Help please solve <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

Inequalities

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$