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notsponge [240]
2 years ago
13

What is the frequency of a wave with speed 3m/s and wavelength 6m?

Physics
1 answer:
Korolek [52]2 years ago
3 0

The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1The frequency of the radio wave is

1

×

10

8

H

z

Explanation:

Let's use the this formula:

C

=

λ

×

v

C represents the speed of light, which has a value of approximately

3.00

×

10

8

m

s

λ

represents the wavelength and the units should be in meters.

v represents the frequency, which should have units of

H

z

or

s

−

1

. Hz is hertz or reciprocal seconds.

Now let's rearrange the equation to solve for v:

C

λ

=

v

v

=

3.00

×

10

8

m

s

/

(

3

m

)

=

1

×

10

8

s

−

1

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A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the
Eva8 [605]

Answer:

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Explanation:

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The speed of the ball after leaving the bat is:

K_2=K_1+W_{nc}\\ \frac{1}{2}mV^2= 85.75 J + 75 J\\ (\frac{1}{2}mV^2)2=( 160.75 J)2\\ mV^2= 321.5 J\\ V^2= \frac{321.5 J}{0.140kg} \\ V=\sqrt{\frac{321.5 J}{0.140kg}}

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V_f^2-V^2=-2gh

V_f^2-(47.92 m/s)^2=-2*9.81m/s^2*25m

V_f^2=-2*9.81m/s^2*25m+(47.92 m/s)^2

V_f=\sqrt{-2*9.81m/s^2*25m+(47.92 m/s)^2}

V_f=42.5m/s

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