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Vlad1618 [11]
3 years ago
9

ILL MARK BRAINLIEST

Physics
1 answer:
Mnenie [13.5K]3 years ago
8 0

Explanation:

2. Power is defined as the rate of doing work. Mathematically, it can be given by :

P=\dfrac{W}{t}

Where

W is work done or energy

t is the time taken

3. The formula of potential energy can be given by :

P=mgh

Where

m is the mass of the object

g is the acceleration due to gravity

h is height

Hence, this is the required solution.

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How many discovered planets are there
Allisa [31]
We have discovered 786 planets. Most of which were only recently discovered.
5 0
3 years ago
If a nucleus decays by successive b, a, a emissions, its mass number will Group of answer choices decrease by seven. decrease by
nirvana33 [79]

Answer:

The mass number will decrease by eight (8).

Explanation:

Given;

successive beta (b), alpha (a), alpha (a) emissions.

Generally, when a radioactive element emits a beta-particle (b), its mass number doesn't increase but its atomic number increases by 1 . (^{0}_{-1}\beta )

Also when a radioactive element emits an alpha-particle (a), its mass number decreases by 4, while its atomic number decrease by 2. (^4_2\alpha)

For the given question, a successive beta (b), alpha (a),  and alpha (a) emissions = (0) + (-4) + (-4) = -8

Thus, when a radioactive element emit a successive beta (b), alpha (a), alpha (a) particles, the mass number will decrease by eight (8).

<u>To learn more, please visit:</u> brainly.com/question/23276969

7 0
3 years ago
PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)
Hoochie [10]

Answer:

False

Explanation:

The ground or surface cannot give off energy

(correct me if i am worng) :)

8 0
3 years ago
You wish to buy a motor that will be used to lift a 10-kg bundle of shingles from the ground to the roof of a house. The shingle
gogolik [260]

Answer:

\tau=19.21\ N-m

Explanation:

It is given that,

Mass of bundle of shingles, m = 10 kg

Upward acceleration of the shingles, a=1.5\ m/s^2

The radius of the motor of the pulley, r = 0.17 m

Let T is the tension acting on the shingles when it is lifted up. It can be calculated as :

T-mg=ma

T=m(g+a)

T=10\times (9.8+1.5)

T = 113 N

Let \tau is the minimum torque that the motor must be able to provide. It is given by :

\tau=r\times T

\tau=0.17\times 113

\tau=19.21\ N-m

So, the minimum value of torque is 19.21 N-m. Hence, this is the required solution.

4 0
3 years ago
Say that you are in a large room at temperature TC = 300 K. Someone gives you a pot of hot soup at a temperature of TH = 340 K.
Sliva [168]

To solve the problem it is necessary to take into account the concepts related to energy efficiency in the engines, the work done, the heat input in the systems, the exchange and loss of heat in the soupy the radius between the work done the lost heat ( efficiency).

By definition the efficiency of the heat engine is

\epsilon = 1- \frac{T_c}{T_h}

Where,

T_c = Temperature at the room

T_h  =Temperature of the soup

The work done is defined as,

dW = \epsilon(dQ_h)

Where Q_h represents the input heat and at the same time is defined as

dQ_h =c_v (dT_h)

Where,

c_V =Specific Heat

The change at the work would be defined then as

dW = \epsilon(dQ_h)

dW = \epsilon c_v (dT_h)

dW = (1-\frac{T_c}{T_h})c_v (dT_h)

W = \int dW = \int (1-\frac{T_c}{T_h})c_v (dT_h)

W = c_v (T_h-T_c)-c_v T_c ln(\frac{T_h}{T_c})

On the other hand we have that the heat lost by the soup is equal to

dQ_h =c_v (dT_h)

Q_h =c_v (T_h-T_c)

The ratio between both would be,

\frac{W}{Q_h} = \frac{c_v (T_h-T_c)-c_v T_c ln(\frac{T_h}{T_c})}{c_v (T_h-T_c)}

\frac{W}{Q_h} = \frac{1+ln(\frac{T_h}{T_c})}{1-\frac{T_h}{T_c}}

Replacing with our values we have,

\frac{W}{Q_h} = 1+\frac{ln(\frac{340K}{300K})}{1-\frac{340K}{300K}}

\frac{W}{Q_h} = 0.0613

Therefore the fraction of heat lost by the soup that can be turned into useable work by the engine is 0.0613.

5 0
3 years ago
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