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2 years ago

What is the rational number equivalent to 3.12 repeated

Mathematics

1 answer:

alisha [4.7K]2 years ago

8 0

3.12...... equal 3 12/99 or 3 4/33. As a result, the final answer will be 103/33. Hope it help!

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Solve the following quadratic equations by any method. The solutions are:

Nataly_w [17]

Answer:

Option C .

Step-by-step explanation:

We would like to solve the below quadratic equation ,

$\longrightarrow f(x) = x^2-12x +32$

Step 1 : Equate f(x) with 0 :-

$\longrightarrow f(x) = 0\\$

$\longrightarrow x^2-12x + 32=0$

Step 2 : Factorise the RHS :-

$\longrightarrow x^2-8x - 4x +32=0\\$

$\longrightarrow x(x-8)-4(x-8)=0\\$

$\longrightarrow (x-8)(x-4)=0\\$

Step 3 : Equate each factor with 0 :-

$\longrightarrow x - 8 = 0\\ \qquad x -4=0$

$\longrightarrow x = 8 \qquad x = 4$

$\longrightarrow \underline{\underline{\boldsymbol{ x = 8,4}}}$

Hence option C is correct .

8 0

1 year ago

Helppp i will mark brainliest <3

hodyreva [135]

Answer:

59.8*4=239.2 rounded to the nearest foot is 239

Step-by-step explanation:

6 0

2 years ago

X+3+5x= x plus three plus five x equal

choli [55]

Answer:

6x+3

Step-by-step explanation:

If you're just combining like terms this is the correct answer

5 0

2 years ago

The stem and leaf plot below shows the number of miles run by members of the cross country team. How many students ran more than

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

Counting from 28 to 44, that is more than 27 miles

28, 31, 32, 33, 35, 39, 42, 43, 44

That is 9 ran more than 27 miles

5 0

2 years ago

Read 2 more answers

**PLEASE HELP ASAP** Betsy is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?

Nina [5.8K]

We analyze the chart and observe that the linear function is $y=x$ , since this relation holds for all values in the table. Drawing this line over the quadratic function shows that they intersect twice, at both the positive and negative x-coordinates.

This is by far the easiest way to solve this problem, but if you're interested in learning how to do it algebraically, read on! To prove this more rigorously, we can find that the equation of the parabola is $y=\frac13 x^2 - 2.$ Substituting in $y=x$ , we find that the intersection points occur where $\frac13 x^2 - 2 = x$ , or $\frac13 x^2 - x - 2 = 0,$ or $x^2 - 3x - 6 = 0.$

This equation doesn't factor nicely, so we use the quadratic formula to learn that $x = \frac{3 \pm \sqrt{3^2 - 4 \cdot 1 \cdot (-6)}}{2} = \frac{3 \pm \sqrt{33}}{2}.$ Hence, the x-coordinates of the intersection points are $\frac{3 + \sqrt{33}}{2}$ , which is positive, and $\frac{3 - \sqrt{33}}{2}$ , which is negative. This proves that there are intersection points on both ends of the axis.

5 0

2 years ago