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Solnce55 [7]
3 years ago
6

PLEASE PLEASE HELP!! Sketch a triangle and label correctly. Work must be shown for this problem. Round answers to the nearest hu

ndredth (2 decimal places).

Mathematics
1 answer:
torisob [31]3 years ago
5 0

Answer:

Please see attached image for the sketch with the labels.

Length "x" of the ramp = 11.70 ft

Step-by-step explanation:

Notice that the geometry to represent the ramp is a right angle triangle, for which we know one of its acute angles (20^o), and the size of the side opposite to it (4 ft). Our unknown is the hypotenuse "x" of this right angle triangle, which is the actual ramp length we need to find.

For this, we use the the "sin" function of an angle in the triangle, which is defined as the quotient between the side opposite to the angle, divided by the hypotenuse, and then solve for the unknown "x" in the equation:

sin(20^o)=\frac{opposite}{hypotenuse}\\ sin(20^o)=\frac{4}{x} \\x=\frac{4}{sin(20^o)} \\x=11.695\,\,ft

Therefore the length of the ramp rounded to the nearest hundredth as requested is: 11.70 ft

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1. By definition, there is a joint variation  when a variable depends on two or more different variables. Therefore, you can express it as following:

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Where x,y and z are the variables and k is the constant of proportionality.

As you can see, y is directly proportional to x and z.

2. Keeping the information above, you have:

I) V=lwh (V varies jointly with l, w and h.

II) V=\frac{1}{3}r^{2}h\pi (If \frac{\pi}{3} is the constant of proportionality, V varies jointly with r^{2} and h).

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Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

Step-by-step explanation:

​(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino. ​

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

  • Probability that a radomly selected resident opposes the casino: P(A)

  • Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the <em>probability that a radomly selected resident opposes the casino</em>, P(A)

Probability = number of favorable outcomes / number of possible outcomes

  • P(A) is <em>given as 60%</em>, which in decimal form is 0.60

ii) Next, determine,the <em>probability that a resident who opposes the casino strongly opposes it</em>, P(B/A):

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iii) You want the probability of both events, which is the joint probability or  intersection: P(A∩B).

So, you can use the definition of conditional probability:

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iv) From which you can solve for P(A∩B)

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(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that <em>a radomly selected resident who opposes the casino does strongly oppose the casino</em>, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

​(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the​ casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

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