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SSSSS [86.1K]
3 years ago
9

What is the volume, in cubic m, of a rectangular prism with a height of 15m, a width of 4m, and a length of 13m?

Mathematics
1 answer:
just olya [345]3 years ago
7 0

Answer:

V = 780 m3

Step-by-step explanation:

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So the question wants to calculate the change of the area among the circles in respect to its radius changes and the best answer would be the following:
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The rate of change are the following:
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Which statement is an axiom of Euclidean geometry? If two lines intersect, their intersection is a plane. If two planes intersec
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If 2 points lie in a plane, the line containing those opints lies in the same plane
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A function f is​ _____ on an open interval I​ if, for any choice of x1 and x2 in​ I, with 1 less than
Zepler [3.9K]

Answer:

If f(x_1)\leq f(x_2) whenever x_1\leq x_2 f is <em>increasing</em> on I.

If f(x_1)\geq f(x_2) whenever x_1\leq x_2 f is <em>decreasing</em> on I.

Step-by-step explanation:

These are definitions for real-valued functions f:I→R. To help you remember the definitions, you can interpret them in the following way:

When you choose any two numbers x_1\leq x_2 on I and compare their image under f, the following can happen.

  • f(x_1)\leq f(x_2). Because x2 is bigger than x1, you can think of f also becoming bigger, that is, f is increasing. The bigger the number x2, the bigger f becomes.
  • f(x_1)\geq f(x_2). The bigger the number x2, the smaller f becomes so f is "going down", that is, f is decreasing.

Note that this must hold for ALL choices of x1, x2. There exist many functions that are neither increasing nor decreasing, but usually some definition applies for continuous functions on a small enough interval I.

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3 years ago
What are the sums of the numbers opposite on a cube ?
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6,8,

Step-by-step explanation:

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For f to be continuous at x=5, we need to have

\displaystyle\lim_{x\to5}f(x)=f(5)

Note that x\to5 means that x\neq5, but that x is *approaching* 5. We're told that for x\neq5, we have

f(x)=\dfrac{x^2-5x}{x^2-25}

We can write

\dfrac{x^2-5x}{x^2-25}=\dfrac{x(x-5)}{(x+5)(x-5)}=\dfrac x{x+5}

and the limit would be

\displaystyle\lim_{x\to5}\frac x{x+5}=\dfrac5{5+5}=\dfrac5{10}=\dfrac12\neq1=f(5)

and so f is discontinuous.
5 0
3 years ago
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