All categories

3 years ago

What is the area of the rectangle? (See attachment)

Mathematics

1 answer:

noname [10]3 years ago

4 0

You need the Pythagorean theorem to solve for the side lengths.

Shorter side:
sqrt(6^2+1^2)=sqrt(37)
Longer side:
sqrt(12^2+2^2)=sqrt(148)

Now multiply the sides together to get:
sqrt(37*148)=sqrt(5476)=74

You might be interested in

Cual es el valor de x si 3(4x-1)=9x-6

zzz [600]

9×6=59 59-6=

-6

----

♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡♡☆♡♡♡♡♡♡♡₩€£+×÷=<>{}[]]espero ter te ajudado meu amigo de♡♡♡♡♡♡♡ fui é essa ai a aconta thau

3 0

2 years ago

Read 2 more answers

15 is what percentage of 25

prisoha [69]

Your answer to this question would be 60 percent hope this helps

6 0

3 years ago

Read 2 more answers

Nahla needs some paint for her bedroom. She finds one can of white paint, three cans of green paint and three cans of blue paint

Lyrx [107]

Answer:

D. 1/7

Step-by-step explanation:

There are seven cans of paint and only one of them are white, so there's a 1/7 of a chance she'll paint her bedroom white.

3 0

2 years ago

Read 2 more answers

Does anyone know the answer to this question

lys-0071 [83]

ANSWER

$\cos B = \frac{ \sqrt{3} }{3}$

EXPLANATION

The given triangle is a right triangle.

It was given that,

$a = 1$

and

$b = \sqrt{2}$

Using the Pythagoras Theorem, we can determine the value of c.

${c}^{2} = {( \sqrt{2} )}^{2} + {1}^{2}$

${c}^{2} = 2 + 1$

${c}^{2} = 3$

$c = \sqrt{3}$

The ratio is the adjacent over the hypotenuse.

$\cos B = \frac{1 }{ \sqrt{3} }$

We rationalize to get:

$\cos B = \frac{ \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } = \frac{ \sqrt{3} }{3}$

3 0

3 years ago

Please help me i don’t understand

kotykmax [81]

537Answer:

Step-by-step explanation:73853ndnxhxnkxgsjdd

8 0

3 years ago