How do i find x and all three sides?

Mathematics

2 answers:

Alexandra [31]3 years ago

6 0

Well,you can use the pythagorean theorem,which is a^2+b^2=c^2 to solve for x.

hram777 [196]3 years ago

5 0

$x+31$ and $2x-59$ are congruent sides

So we have
$2x-59=x+31$
⇒ $x-59=31$
⇒ $x=90$

Plug in:
$x+31=90+31=121$
$2x-59=2(90)-59=180-59=121$
$x-7=90-7=83$

You might be interested in

If the given values in a right triangle are cos A =

Vlad1618 [11]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2