It give you two point, (2,4)(-1, -1).
f(x)=mx+b
2m+b=4
-m+b=-1
2m+b+m-b=5
3m=5
m=5/3
b=2/3
f(x)=5/3x+2/3
Answer:
6
Step-by-step explanation:
Any circle in the form

Where r^2 is the radius squared, so


I am not sure about point slope, but I can find an equation in slope-intercept form and convert it, so
y=mx+b, m=slope
slope=(y1-y2)/(x1-x2)
we have points
(4,5)
(-3,-1)
(x,y)
x1=4
y1=5
x2=-3
y2=-1
subsitute
(5-(-1))/(4-(-3))=(5+1)/(4+3)=6/7
y=6/7+b
sybsitute and solve for b
(4,5)
x=4
y=5
5=6/7(4)+b
5=24/7+b
5=35/7
subtract 24/7 from both sides
11/7=b
y=6/7x+11/7
convert to the point slope form and find equivilent fraction
since the question asks for 2 answers that are correct and only 2 of the equations have slope of 6/7 I can guess that the answers are B and C
Answer:
c
Step-by-step explanation:
answer is c on edg
Answer:
The graphs of the two function will not intersect.
Step-by-step explanation:
We are given a quadratic function f(x).
Also g(x) is given by a set of values as:
x g(x)
1 -1
2 0
3 1
As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c
let g(x)=y
when x=1 , g(x)=-1
-1=m+c----(1)
when x=2 , g(x)=0
0=2m+c------(2)
Hence, on solving (1) and (2) by method of elimination we get:
m=1 and c=-2
Hence, the equation of g(x) is:
g(x)=x-2
So clearly from the graph we could see that the graph of the two functions will never intersect.