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QveST [7]
3 years ago
6

13 143 as a unit fraction

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0
Divde 13/143 with 13 = 1/11
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In the number 514,482,441, how is the relationship between the first pair of 4s the same as the relationship between the second
yanalaym [24]
In the 1st pair of fours the 4 on the left side is 10 times greater than the 4 on the right. The same thing with the 2nd pair of fours. The 4 on the left side is 10 greater than the 4 on the right. Hope this helps!

3 0
3 years ago
Read 2 more answers
Y = (1/4)x^2 - (1/2)lnx..over the interval (1, 7e) ...what is the arc length ?
xenn [34]
So, f[x] = 1/4x^2 - 1/2Ln(x) 
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
6 0
3 years ago
What is the equation of the graph below?
IgorC [24]
ANSWER

f(x) = (x  +  3)^{2}  - 1



EXPLANATION

The vertex of the graph is at


(-3,-1)


The equation of the graph in vertex form is given by the formula,



f(x) =  a{(x - h)}^{2}  + k


The above graph has a minimum point, hence
a >  \: 0

When we put these values into the equation we obtain,

f(x) = a(x -  - 3)^{2}   +  - 1


This implies that,

f(x) = a(x  +  3)^{2} - 1

The point (-2,0) lies on the line.


a( - 2 + 3)^{2}    - 1 = 0

a = 1


f(x) = (x  + 3)^{2}  - 1

The correct answer is D.
6 0
3 years ago
A realtor collects the data set given in DS 12.2.4 concerning the sizes of a random selection of newly constructed houses in a c
Yuliya22 [10]

The table is missing in the question. The table is attached below.

Solution :

Let X = appraised value

    Y = area (square feet)

The regression line is given by :

$\hat y = b_0+b_1X$

$b_1=\frac{n\sum XY-\sum X \sum Y}{n \sum X^2-(\sum X)^2}$

   $=\frac{15(5964990)-(2157)(33370)}{15(404799)-(2157)^2}$

  $=12.3267$

$b_0=\frac{\sum Y}{n}-b_1\frac{\sum X}{n}$

   $=\frac{33370}{15}-\left(12.3267 \times \frac{2157}{15}\right)$

  $b_0=452.0841$

The regression line is :

$\hat Y = 452.0841+12.3267 X$

To estimate the error variance, we have:

Error variance, $\sigma =\sqrt{\frac{\sum (Y-\hat Y)^2}n-2{}}$

                           $=\sqrt{\frac{587682.3}{15-2}}$

                            $=212.6178$

8 0
3 years ago
PLEASE HELP!!! You must show your work to receive credit for this item.
Natalka [10]
The answer to this question is 12
8 0
3 years ago
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