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Alex
3 years ago
15

a. Determine whether the Mean Value Theorem applies to the function f (x )equals ln 15 xf(x)=ln15x on the given interval [1 comm

a e ][1,e]. b. If​ so, find or approximate the​ point(s) that are guaranteed to exist by the Mean Value Theorem.
Mathematics
1 answer:
ivolga24 [154]3 years ago
5 0

Answer:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

c = e-1 \\ = 1.71828

Step-by-step explanation:

(a)

The function f is continuous at [1,e] and differentiable at (1,e), therefore

the mean value theorem applies to the function.

(b)

You are looking for a point c   such that

\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}

You have to solve for c  and get that

c = e-1 \\ = 1.71828

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PLS ANSWER ASAP!!!!!<br> Simplify 5^-4/5^3
Alekssandra [29.7K]

Answer:

None on the above.

Step-by-step explanation:

Here’s what I got:

1/5^-1.

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5 0
2 years ago
What is the result when 6x3 + 11x2 + 9x + 2 is divided by 3x + 1?
konstantin123 [22]

<u>Answer:</u>

<u>(6x^(3)+11x^(2)-19x+5)-:-(3x-2)</u>

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4 0
3 years ago
Solve the equation. Check your solution. - 6y + 5 = 29y - 2​
mr_godi [17]

Answer:

y = 0.2

Step-by-step explanation:

Simplifying

-6y + 5 = 29y + -2

Reorder the terms:

5 + -6y = 29y + -2

Reorder the terms:

5 + -6y = -2 + 29y

Solving

5 + -6y = -2 + 29y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-29y' to each side of the equation.

5 + -6y + -29y = -2 + 29y + -29y

Combine like terms: -6y + -29y = -35y

5 + -35y = -2 + 29y + -29y

Combine like terms: 29y + -29y = 0

5 + -35y = -2 + 0

5 + -35y = -2

Add '-5' to each side of the equation.

5 + -5 + -35y = -2 + -5

Combine like terms: 5 + -5 = 0

0 + -35y = -2 + -5

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Combine like terms: -2 + -5 = -7

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Divide each side by '-35'.

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Simplifying

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3 0
3 years ago
Read 2 more answers
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4 0
3 years ago
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