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3 years ago

Find a formula for a function f(x,y,z) whose level surface f=81 is a sphere of radius 9, centered at the origin.

Mathematics

1 answer:

Mrrafil [7]3 years ago

4 0

$81(9 \times 8 = 72 + 9) = 81$

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PLEASE HELP ME WITH GEOMETRY PLS AND TANKYOU

mart [117]

Answer:

Step-by-step explanation:

because 180-44=136

136:2=68 (since TRS=TSR, there is formula)

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2 years ago

Help! Find the domain of the graph

charle [14.2K]

Answer:

[-8,4]

Step-by-step explanation:

you look at the x-axis. The end points of the graph are -8 and 4, thus the domain would be [-8,4] as it is always written in left to right or bottom to top value.

hope it helps.

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3 years ago

Which function has a greater rate of change

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Answer:

A has a rate of change of -5 and is greater than Bs -4.5

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3 years ago

If the 6th term of an arithmetic progres- sion is 11 and the first term is 1, find the common difference.

Darina [25.2K]

Answer:

Step-by-step explanation:

An arithmetic progression with first term a and common difference d has the following first 6 terms:

a, a + d, a + 2d, a + 3d, a + 4d, a + 5d

We are given a = 1 and a + 5d = 11.

1 + 5d = 11

5d = 10

d = 2

Answer: The common difference is 2.

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2 years ago

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

8 0

4 years ago