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3 years ago

Please please help me!!!

Mathematics

1 answer:

shutvik [7]3 years ago

6 0

Answer:

Step-by-step explanation:

Suppose she only fills her big pots. The number of big pots filled is 120÷12=10. So the y-intercept is (0,10).

Now suppose she only fills her small pots. The number of small pots filled is 120÷5=24. So the x-intercept is (24,0)

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PLEASE HELP THIS QUESTION IS SO ANNOYING!!

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ANSWER- 23 , 76

Explanation- just did it :)

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2 years ago

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A watermelon that weights 4 pounds how many kilograms is the watermelon?

timama [110]

1.814 kg is equal to 4 pounds

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2 years ago

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Bobby wants to go on a school trip that will cost him $250. He comes up with an equation that represents how much he needs to sa

monitta

Yes, Bobby will have enough money if he saves for 9 weeks. You can find this through either substituting w for 9 in the equation, or solving the equation itself.

Substituting:

$25(9)+30$
Substitute w for 9.

$225+30$
Simplify.

$225+30=255$
Solve.

255 is greater than 250, so yes, he will have enough money saved.

Solving the equation:

$25w+30=250$
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$25w=220$
Subtract 30 from both sides.

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3 years ago

Somebody please help and explain it.

s2008m [1.1K]

Explanation is in the file

tinyurl.com/wpazsebu

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2 years ago

Find the limit, if it exists, or type dne if it does not exist.

Phantasy [73]

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

$\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1$

On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

The value of the limit then depends on $k$ , which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.

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3 years ago